psql 在聚合 function 上过滤行

Question

我有下表：

+------+-----------+-------------+--------------+
| year | team_name | player_name | total_points |
+------+-----------+-------------+--------------+
| 1992 | Magic     | Shaq        | 2000         |
+------+-----------+-------------+--------------+
| 1992 | Magic     | Steve Kerr  | 4000         |
+------+-----------+-------------+--------------+
| 1996 | Lakers    | Shaq        | 2300         |
+------+-----------+-------------+--------------+
| 1996 | Lakers    | Magic       | 1000         |
+------+-----------+-------------+--------------+
| 2004 | Heat      | Shaq        | 3000         |
+------+-----------+-------------+--------------+

我正在尝试编写一个查询来查找沙克得分最高的所有球队。

这是我的尝试：

SELECT year, team, MAX(total_points) FILTER(WHERE player_name = 'Shaq'
FROM basketball
GROUP BY year, team;

这显然是不正确的。 我认为我错误地使用了 FILTER，因为我无法找到 Shaq 在该球队中得分最高的球队

正确的表应该只有第三行和最后一行

Answer 1

你很亲密。 您想要一个HAVING子句将球队的年度最高分与沙克的积分进行比较，并且只保留匹配的那些。

SELECT year, team, MAX(total_points)
FROM basketball
GROUP BY year, team
HAVING MAX(total_points) = MAX(total_points) FILTER (WHERE player_name = 'Shaq');

Answer 2

询问 -

select year, team_name,high_score from (
  select *, 
  max(total_points) over (partition by year, team_name) high_score 
  from basketball) t
where t.total_points = t.high_score
and t.player_name='Shaq'

小提琴。