在 switch 语句中执行 while 循环

Question

仅使用 switch 语句就可以了。 我的问题是在插入 do-while 循环时出现的。 在第一次尝试时，程序运行顺利，但在第二次和随后的循环中，在通过键入 1 询问用户是否想再试一次之后，程序“跳转”用户写入其输入的部分（scanf("% d", &oper)) 并执行程序的 rest，将先前键入的 1 作为输入并搞砸一切。

我试过寻找类似问题和视频的答案，但我很新，我无法理解。 我有另一个有类似问题的程序。 我将非常感谢您的帮助:)

#include <stdio.h>

int main()
{
    int num1, num2, oper, select;
    printf("Enter the first number:");
    scanf("%d", &num1);
    printf("Enter the second number:");
    scanf("%d", &num2);
    printf("Enter the number 1-5 to for the operations\n");
    printf("1-Addition\n");
    printf("2-Subtraction\n");
    printf("3-Division\n");
    printf("4-Multiplication\n");
    printf("5-Modulo\n");
    
    scanf("%d", &oper);
    
    do{
        printf("Press 0 to stop and 1 to continue");
        scanf("%d", &select);
    
        switch(oper){
             case 1:
             printf("The sum is %d\n", num1+num2);
             break;
             case 2:
             printf("The difference is %d\n", num1-num2);
             break;
             case 3:
             printf("The quotient is %d\n", num1/num2);
             break;
             case 4:
             printf("The product is %d\n", num1*num2);
             break;
             case 5:
             printf("The remainder is %d\n", num1%num2);
             break;}
        
        
    }while(select == 1);
} ```

Answer 1

我想你想要类似下面的代码。

尝试这个：

#include <stdio.h>

int main()
{
    int num1, num2, oper, select;
    do{
        printf("Enter the first number:");
        scanf("%d", &num1);
        printf("Enter the second number:");
        scanf("%d", &num2);
        printf("Enter the number 1-5 to for the operations\n");
        printf("1-Addition\n");
        printf("2-Subtraction\n");
        printf("3-Division\n");
        printf("4-Multiplication\n");
        printf("5-Modulo\n");
        
        scanf("%d", &oper);
        switch(oper){
             case 1:
             printf("The sum is %d\n", num1+num2);
             break;
             case 2:
             printf("The difference is %d\n", num1-num2);
             break;
             case 3:
             printf("The quotient is %d\n", num1/num2);
             break;
             case 4:
             printf("The product is %d\n", num1*num2);
             break;
             case 5:
             printf("The remainder is %d\n", num1%num2);
             break;
         }
        
        printf("Press 0 to stop and 1 to continue: ");
        scanf("%d", &select);
    } while(select == 1);
    printf("Finish");
}

Answer 2

更改以下代码： while(select;= 0);

Answer 3

尝试这个：

#include <stdio.h>

int main()
{
    int num1, num2, oper, select;
    printf("Enter the first number:");
    scanf("%d", &num1);
    printf("Enter the second number:");
    scanf("%d", &num2);
    printf("Enter the number 1-5 to for the operations\n");
    printf("1-Addition\n");
    printf("2-Subtraction\n");
    printf("3-Division\n");
    printf("4-Multiplication\n");
    printf("5-Modulo\n");
    
    scanf("%d", &oper);
    
    do{
      printf("Press 0 to stop and 1 to continue");
      scanf("%d", &select);
  
      switch(oper){
        case 1:
        printf("The sum is %d\n", num1+num2);
        break;
        case 2:
        printf("The difference is %d\n", num1-num2);
        break;
        case 3:
        printf("The quotient is %d\n", num1/num2);
        break;
        case 4:
        printf("The product is %d\n", num1*num2);
        break;
        case 5:
        printf("The remainder is %d\n", num1%num2);
        break;
      }
           
    }while(select != 0);
}