[英]List parsing in Java/Groovy
我喜欢解析以下列表。
LUT = [
[branch: "test", name: 'a', image_name: 'abc'],
[branch: "test", name: 'b', image_name: 'abc'],
[branch: "test", name: 'c', image_name: 'abc'],
[branch: "test-1", name: 'd', image_name: 'abc'],
[branch: "test-1", name: 'e', image_name: 'abc'],
[branch: "test-2", name: 'f', image_name: 'abc'],
[branch: "test-2", name: 'g', image_name: 'abc'],
[branch: "test-2", name: 'h', image_name: 'abc'],
[branch: "test-3", name: 'i', image_name: 'abc'],
[branch: "test-3", name: 'j', image_name: 'abc'],
[branch: "test-4", name: 'k', image_name: 'abc'],
[branch: "test-5", name: 'l', image_name: 'abc'],
]
现在我要做的是:
result = [:]
for (map in LUT)
{
if (!result.containsKey(map['branch']))
{
println map['name'] // prints the unique name
result.put(map['branch'], map['name'])
}
}
这将在列表中生成 1 对 1 map:
[test:a, test-1:d, test-2:f, test-3:i, test-4:k, test-5:l]
但我想要的是一个列表列表,如:
[test:[a:abc], test-1:[d:abc], test-2:[f:abc], test-3:[i:abc], test-4:[k:abc], test-5:[l:abc]]
谁能帮我解决这个问题,谢谢
我不知道 groovy 但我想我可以提供帮助。
而不是这个:
result = [:]
for (map in LUT)
{
if (!result.containsKey(map['branch']))
{
println map['name'] // prints the unique name
result.put(map['branch'], map['name'])
}
}
你需要这样的东西:
result = [:]
for (map in LUT)
{
if (!result.containsKey(map['branch']))
{
println map['name'] // prints the unique name
newMap = [:]
newMap.put(map['name'], map['image_name'])
result.put(map['branch'], newMap)
}
}
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