SQL 查询查找记录属于两种状态

Question

cust_id	state
1	加州
2	伊利诺伊州
3	SC
1	功放
3	IA
4	莫
5	弗吉尼亚州
4	纽约

任何人都可以请关于 SQL 查询返回属于以下两种状态的 cust_id：

output 应该是

cust_id	state
1	加州
1	功放
3	SC
3	IA
4	纽约
4	莫

Answer 1

尝试以下查询

解决方案 1

Select * From yourtable
Where Cust_Id In (Select cust_id From yourtable Group By cust_id Having 
Count(*) = 2) Order By cust_id,state

解决方案 2

With T1 As 
(Select cust_id From yourtable Group By cust_id Having Count(*) = 2) 
Select T2.* From yourtable T2 Join T1 On T1.cust_id = T2.cust_id O 
Order By T2.cust_id,T2.state

Answer 2

SELECT * FROM yourtable t1
JOIN
(SELECT cust_id,COUNT(DISTINCT state) AS cnt 
   FROM yourtable  GROUP BY cust_id HAVING cnt =2) t2
ON t1.cust_id=t2.cust_id
ORDER BY t1.cust_id,t2.state

Answer 3

SELECT tmp.*
   FROM tmp
 INNER JOIN (
    SELECT cust_id
        ,COUNT(STATE) s_count
    FROM tmp
    GROUP BY [cust_id]
) sub 
ON tmp.cust_id = sub.cust_id
 WHERE sub.s_count = 2
 ORDER BY cust_id
    ,STATE

Answer 4

一种简单的方法是使用COUNT window function，这将分配每个“ cust_id ”在您的表中出现的次数。 获得此值后，您可以过滤掉计数小于 2 的行。

WITH cte AS (
    SELECT *, COUNT(cust_id) OVER(PARTITION BY cust_id) AS cnt 
    FROM tab
)
SELECT cust_id,
       state
FROM cte 
WHERE cnt > 1

在此处查看演示。