不间断地在java中创建一个猜数游戏，继续循环返回

Question

我正在写一个猜谜游戏。 游戏应该选择一个介于 1 和 99（含）之间的随机数，然后在您选择合适的数字后，您会收到“成功”消息。 我只能尝试 5 次。 我想我需要做一些try-catch 、 if-else和循环以确保获得所有异常。 不写一个int会给你一个InputMismatchException并让你再试一次，但你不会失去“生命”你仍然有 5/5 或 3/5 次尝试（这取决于你在游戏中完成的进度）。 数字超过限制也是一样。

例子：

(1/5) 0 < ? < 100 : 50
(2/5) 50 < ? < 100 : 75
(3/5) 50 < ? < 75 :

（部分为法文）

感谢您的时间！

https://i.stack.imgur.com/ovt1m.png

https://i.stack.imgur.com/abtPa.png

import java.util.InputMismatchException;
import java.util.Random;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        Random r = new Random();
        int nbGenere = r.nextInt(100); 
        int nb1; // first number from user
        int nb2; // second number from user
        int borneMini; // minimum
        int borneMax; // max
        boolean valide1 = false; // variable do #1
        boolean valide2 = false; // variable do #2
        System.out.println(nbGenere);
        System.out.print("You got 5 tries to find a number 1 and 99 (inclusive)\n(1/5) 0 < ? < 100: ");
        do { // do #1
            try {
                nb1 = scan.nextInt();
                borneMini = 0;
                borneMax = 100;
                valide1 = nb1 > borneMini && nb1 < borneMax;
                if (!valide1)
                    System.out.print("Enter a valide number 1\n(1/5)" + borneMini + " < ? < " + borneMax + ": ");
                else if (nb1 == nbGenere)
                    System.out.print("Success!");
                else if (nb1 < nbGenere)
                    System.out.print("(2/5) " + nb1 + " < ? < 100: ");
                else
                    System.out.print("(2/5) 0 < ? < " + nb1 + ": ");
            } catch (InputMismatchException e) {
                System.out.print("Enter a valide number 2\n(1/5)\" + borneMini + \" < ? < \" + borneMax + \": ");
                scan.nextLine();
            }
            do { // #2
                try {
                    nb2 = scan.nextInt();
                    if (nb1 < nbGenere)
                        borneMini = nb1;
                    else
                        borneMini = 0;

                    if (nb1 > nbGenere)
                        borneMax = nb1;
                    else
                        borneMax = 100;

                    valide2 = ((nb1 > nb2 || nb1 < nb2) && nb1 > borneMini && nb1 < borneMax);
                    if (!valide2)
                        System.out.print("Enter a valide number 3\n(2/5)" + borneMini + " < ? < " + borneMax + ": ");
                    else if (nb2 == nbGenere)
                        System.out.print("success!");
                    else if (nb1 > nb2 )
                        System.out.print();
                } catch (InputMismatchException f) {
                    System.out.print("Enter a valide number 4\n(2/5");
                }
            } while (!valide2);
        } while (!valide1);
    }
}

Answer 1

int nbGenere = r.nextInt(100);

根据文档，此方法可能返回 0（零），这不是您想要的。 最好使用方法nextInt(int, int) ，即

int nbGenere = r.nextInt(1, 100);

您只需要一个do-while循环，并且需要一个变量来跟踪猜测的次数。

如果用户输入的数字不在有效范围内，您可以抛出异常，因为您对非数字和不在可接受范围内的数字使用相同的处理。

import java.util.InputMismatchException;
import java.util.Random;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        Random r = new Random();
        int nb1; // number from user
        int borneMini = 0; // minimum
        int borneMax = 100; // maximum
        int nbGenere = r.nextInt(borneMini + 1, borneMax); 
        boolean valide1 = false;
        boolean valide2 = false; // variable do #1
        System.out.println(nbGenere);
        System.out.println("You have 5 tries to find a number between 1 and 99 (inclusive).");
        int tries = 5; // total guesses allowed
        int attempt = 1; // guess number
        do { // do #1
            System.out.printf("(%d/%d) %2d < ? < %3d : ", attempt, tries, borneMini, borneMax);
            try {
                nb1 = scan.nextInt();
                valide1 = nb1 > borneMini && nb1 < borneMax;
                if (!valide1) {
                    throw new InputMismatchException();
                }
                else if (nb1 == nbGenere) {
                    System.out.println("Success!");
                    valide2 = true;
                }
                else if (nb1 < nbGenere) {
                    attempt++;
                    borneMini = nb1 - 1;
                }
                else {
                    attempt++;
                    borneMax = nb1 + 1;
                }
            } catch (InputMismatchException e) {
                System.out.printf("Enter a valid number between %d and %d.%n", borneMini, borneMax);
                scan.nextLine();
            }
        } while (!valide2 && attempt <= tries);
        if (!valide2) {
            System.out.println("Better luck next time. The mystery number was " + nbGenere);
        }
    }
}

样本运行中的 Output：

65
You have 5 tries to find a number between 1 and 99 (inclusive).
(1/5)  0 < ? < 100 : 500
Enter a valid number between 0 and 100.
(1/5)  0 < ? < 100 : 50
(2/5) 49 < ? < 100 : 75
(3/5) 49 < ? <  76 : 62
(4/5) 61 < ? <  76 : 68
(5/5) 61 < ? <  69 : 65
Success!

另一个示例运行：

64
You have 5 tries to find a number between 1 and 99 (inclusive).
(1/5)  0 < ? < 100 : 50
(2/5) 49 < ? < 100 : foo
Enter a valid number between 49 and 100.
(2/5) 49 < ? < 100 : 75
(3/5) 49 < ? <  76 : 8
Enter a valid number between 49 and 76.
(3/5) 49 < ? <  76 : 62
(4/5) 61 < ? <  76 : 67
(5/5) 61 < ? <  68 : 66
Better luck next time. The mystery number was 64

Answer 2

不太确定为什么你有两个 do while 循环但你正在寻找的可能看起来像这样

        public void gameLoop(Scanner scanner, int life){
        int input;
        int number;
        int lifeRemaining = life;
        do {
            try {
                input = Integer.parseInt(scanner.nextLine());
            } catch (NumberFormatException e) {
                System.err.println("Wrong input! Input only integer numbers please: " + e.getMessage());
            }
            //check if valid based on game rule
            if(!inputCheck(input)){
                //do sth
            }else{
                //only comes here if input is valid
                if(input > number){
                    //print sth
                    lifeRemaining--;
                }
                if(input<number){
                    //print sth
                    lifeRemaining--;
                }
                if(input==number){
                    //print sth
                    lifeRemaining--;
                }
            }
        }while(lifeRemaining>0);
        //game over
   }