如何在您进行所需活动时禁用所有传入的推送通知？

Question

正如标题所暗示的那样，当我处于所需的活动中时，如何防止我的应用程序收到通知？ 我正在开发一个聊天应用程序，其中用户可以在发布新消息时收到通知，当用户处于聊天活动中时如何阻止通知？

这是 FirebaseMessagingService：

public class MyFirebaseMessagingService extends FirebaseMessagingService {

    @Override
    public void onMessageReceived(@NonNull RemoteMessage message) {
        super.onMessageReceived(message);

        int requestID = (int) System.currentTimeMillis();

        String title = message.getNotification().getTitle();
        String body = message.getNotification().getBody();
        String click_action=message.getNotification().getClickAction();

        NotificationCompat.Builder builder = new NotificationCompat.Builder(getApplicationContext(),"Notification");
        builder.setContentTitle(title);
        builder.setContentText(body);
        builder.setSound(Settings.System.DEFAULT_NOTIFICATION_URI);
        builder.setVibrate(new long[] { 1000, 1000, 1000, 1000, 1000 });
        builder.setLights(getResources().getColor(R.color.chitchat), 3000, 3000);
        builder.setSmallIcon(R.drawable.logowhite);

        Intent intent = null;
        //message.getData().get("type");
        
        if (Objects.requireNonNull(message.getData().get("type")).equalsIgnoreCase("privatechat")) 
       {
            intent = new Intent(click_action);
            intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK  | Intent.FLAG_ACTIVITY_CLEAR_TASK);
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
            intent.putExtra("GCKey", message.getData().get("GCKey"));
            intent.putExtra("GCNameKey", message.getData().get("GCNameKey"));
        }

        PendingIntent pendingIntent = PendingIntent.getActivity(this, requestID, intent, PendingIntent.FLAG_UPDATE_CURRENT | PendingIntent.FLAG_IMMUTABLE );
        builder.setAutoCancel(true);
        builder.setContentIntent(pendingIntent);
        
        NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            NotificationChannel channel = new NotificationChannel("Notification", "Default channel", NotificationManager.IMPORTANCE_DEFAULT);
            notificationManager.createNotificationChannel(channel);
        }
        notificationManager.notify(69, builder.build());
    }
}

Answer 1

这应该不难。 您可以只创建一个 class，其中您有一个 static 变量，您只需在其中设置活动并在通知之前检查是否要显示通知。 这将 go 这样：

1. 使用 static 变量创建一个新的 class

    public class NotificationHelper { public static boolean shouldShowNotification = true; }

2. 在您不希望通知显示的活动中添加此代码：

    @Override public void onResume(){ super.onResume(); NotificationHelper.shouldShowNotification = false; } @Override public void onPause(){ super.onPause(); NotificationHelper.shouldShowNotification = true; }

3. 在MyFirebaseMessagingService class 中，在执行代码之前添加一个条件。

    public class MyFirebaseMessagingService extends FirebaseMessagingService { @Override public void onMessageReceived(@NonNull RemoteMessage message) { super.onMessageReceived(message); if(NotificationHelper.shouldShowNotification){ // your code goes here... } } }