按日期和活动顺序分区

Question

我有一张桌子：

| Title    | Expire_date | Active |
| -------- | --------    |--------|
| Apple    | 01-01-2023  |1       |
| Banana   | 01-01-2022  |1       |
| Orange   | 01-06-2021  |1       |
| Banana   | 01-01-2021  |0       |
| Apple    | 01-01-2021  |0       |
| Apple    | 01-01-2020  |0       |
| ...      | ...         |...     |
| Fruit_999| 01-01-2020  |1       |

并希望获得结果形式选择如下所示：

标题	到期日期	积极的
水果_999	01-01-2020	1个
橙子	01-06-2021	1个
香蕉	01-01-2022	1个
香蕉	01-01-2021	0
苹果	01-01-2023	1个
苹果	01-01-2021	0
苹果	01-01-2020	0
...	...	...

因此，首先它应该按活动顺序排序，然后按过期日期排序，然后按标题对结果进行分组。

1）在这里不起作用，它不会按标题分组。

ORDER BY expire_date, active

2) 将Apple 放在最前面，虽然Orange 和Fruit_999 日期较少，但这是错误的

SELECT * FROM `table` ORDER BY MIN(`expire_date`) OVER (PARTITION BY `title`), `active` DESC;

Answer 1

试试这个。 查询将按第一列对行进行排序，然后在不破坏第一条规则的情况下按第二列进行排序。 然后，以同样的方式，在不违反现有规则的情况下，根据第三等。

SELECT * FROM `events` ORDER BY Title DESC, Expire_date ASC

Answer 2

您应该使用分析函数 (oracle) 或窗口函数 (MSSQL)... 来实现您的预期结果。

因为您没有标记您的 RDBMS，所以这是对 Oracle 的运行查询。 转换它以适合您的 RDBMS。

WITH table_name AS 
(
    SELECT  'Apple' AS Title, TO_DATE('01-01-2023', 'DD-MM-YYYY') AS expire_date,  1 AS active FROM dual UNION ALL      
    SELECT  'Banana' AS Title, TO_DATE('01-01-2022', 'DD-MM-YYYY') AS expire_date,  1 AS active FROM dual UNION ALL      
    SELECT  'Orange' AS Title, TO_DATE('01-06-2021', 'DD-MM-YYYY') AS expire_date,  1 AS active FROM dual UNION ALL      
    SELECT  'Banana' AS Title, TO_DATE('01-01-2021', 'DD-MM-YYYY') AS expire_date,  0 AS active FROM dual UNION ALL      
    SELECT  'Apple' AS Title, TO_DATE('01-01-2021', 'DD-MM-YYYY') AS expire_date,  0 AS active FROM dual UNION ALL      
    SELECT  'Apple' AS Title, TO_DATE('01-01-2020', 'DD-MM-YYYY') AS expire_date,  0 AS active FROM dual UNION ALL      
    SELECT  'Fruit_999' AS Title, TO_DATE('01-01-2020', 'DD-MM-YYYY') AS expire_date,  1 AS active FROM dual 
),
title_active AS
(
    SELECT Title, 
        MIN(CASE WHEN active = 1 THEN expire_date ELSE TO_DATE('01-01-3000', 'DD-MM-YYYY') END) AS min_active_expire_date, 
        MAX(active) AS max_active
    FROM table_name
    GROUP BY title
),
title_ordered AS 
(
    SELECT ROW_NUMBER() OVER (ORDER BY max_active DESC, min_active_expire_date) AS rn,
        t.*
    FROM title_active t
)
SELECT t.title, t.expire_date, t.active--*
FROM table_name t
INNER JOIN title_ordered ti
ON t.title = ti.title
ORDER BY ti.rn, t.active DESC, t.expire_date;

使用sqlfiddle测试

P/S：这个查询应该可以工作大约 978 年。 在那之后，如果你继续运行，这个查询可能会返回错误的结果......

Answer 3

尝试以下操作：

select * from table_name
order by max(Expire_date) over (partition by Title),
         Title, Active desc, Expire_date

这将根据每个标题的最新 Expire_date 对行进行排序，日期最早的标题首先出现。 如果有两个具有相同 max(Expire_date) 的标题，则按标题排序以保持标题连续（成组）。 对于相同标题（相同最大日期）内的行，按活动降序排序以首先显示每个标题的活动行。

看演示。