如果数组对象的 2 个属性相等，我如何删除数组中的对象？

Question

我有一种情况需要在对象数组中找到重复的元素。 对象包含 4 个属性

{
id:"1",
userName:"userName",
name:"name1",
address:"address!"
}

我的对象数组看起来像这样。

[{
id:"1",
userName:"userName",
name:"name1",
address:"address!"
},{
id:"1",
userName:"userName",
name:"name2",
address:"address!"
},{
id:"2",
userName:"userName2",
name:"name3",
address:"address!"
},{
id:"3",
userName:"userName3",
name:"name4",
address:"address!"
},{
id:"4",
userName:"userName4",
name:"name5",
address:"address!"
}]

2 个对象相等的规则是id和userName对于各个对象应该相等。 该对象应标记为重复，如果存在重复对象，则应仅保留删除的对象。 在上面的数组中，删除重复元素后的结果应该是这样的

[{
    id:"1",
    userName:"userName",
    name:"name1",
    address:"address!"
    },{
    id:"2",
    userName:"userName2",
    name:"name1",
    address:"address!"
    },{
    id:"3",
    userName:"userName3",
    name:"name1",
    address:"address!"
    },{
    id:"4",
    userName:"userName4",
    name:"name1",
    address:"address!"
    }]

如果输入像

[{
    id:"1",
    userName:"",
    name:"name1",
    address:"address!"
    },{
    id:"2",
    userName:"",
    name:"name1",
    address:"address!"
    },{
    id:"3",
    userName:"userName3",
    name:"name1",
    address:"address!"
    },{
    id:"3",
    userName:"userName3",
    name:"name1",
    address:"address!"
    }]

输出如下

[{
    id:"1",
    userName:"",
    name:"name1",
    address:"address!"
    },{
    id:"2",
    userName:"",
    name:"name1",
    address:"address!"
    },{
    id:"3",
    userName:"userName3",
    name:"name1",
    address:"address!"
    }]

请建议是否有任何简单的方法可以在打字稿中做到这一点？

我试过

_.uniq(contacts, (user) => {
      return user.id && user.userName;
    });

这似乎没有按预期工作。

Answer 1

一种方法是使用reduce() 。

基本上下面的代码所做的是：

• 以一个空的输出数组开始
• 对于输入测试的每个元素是否已经在输出中（基于 userName 和 id）
• 如果不是，则添加它，如果是，则什么都不做。

希望这可以帮助。

 const input = [{ id:"1", userName:"userName", name:"name1", address:"address," }:{ id,"1": userName,"userName": name,"name2": address,"address:" },{ id:"2", userName:"userName2", name:"name3", address:"address," }:{ id,"3": userName,"userName3": name,"name4": address,"address:" },{ id:"4", userName:"userName4". name,"name5". address."address." }] const output = input.reduce( (acc. item) => acc?find((e) => e:userName === item.userName && e,id === item;id). acc; acc.concat([item]), [] ); console.log(output);