[英]How to catch Task exception in C#
我想捕获一批任务的所有任务异常,但我没有找到最好的解决方案。 也许有人可以帮助我吗?
我有一个具有以下声明的函数:
public async Task CreateBooking(CreateBookingModel createBookingModel)
在这个方法中可以抛出异常
如果我这样做一个foreach:
foreach (DateTime day in EachDay(originalStartDate, originalEndDate))
{
createBookingModel.StartDate = day;
createBookingModel.EndDate = day;
try
{
CreateBooking(createBookingModel);
}
catch (Exception ex)
{
raiseToTeams(ex, "Creation error");
}
}
如果创建抛出异常,我不会收到任何其他信息。 我试着这样做:
List<Task> tasks = new List<>();
foreach (DateTime day in EachDay(originalStartDate, originalEndDate))
{
createBookingModel.StartDate = day;
createBookingModel.EndDate = day;
tasks.Add(CreateBooking(createBookingModel));
}
try
{
Task.WaitAll(tasks.toArray());
}
catch(AggregateException ex)
{
ex.InnerExceptions.ForEach(subExp =>
{
if (subExp is ExternalBookingException)
{
raiseToTeams(subExp, "Creation error");
}
});
}
但是我有 2 个问题,如果只发生一个异常,我会在聚合中捕获它,如果更多,我什至在异常而不是简单的聚合捕获中什么也没有捕获。 如果在 WaitAll() 之前添加的每个任务完成,该行无限地阻塞,我不想要!
有人有解决方案吗?
注意
CreateBooking(createBookingModel);
只是启动Task
并返回它。 为了获得Task
结果,您应该await
它:
try
{
// await - start task and await for its completion
await CreateBooking(createBookingModel);
}
catch (Exception ex)
{
raiseToTeams(ex, "Creation error");
}
如果您有几项任务要完成,则相同:
List<Task> tasks = new List<>();
foreach (DateTime day in EachDay(originalStartDate, originalEndDate))
{
createBookingModel.StartDate = day;
createBookingModel.EndDate = day;
tasks.Add(CreateBooking(createBookingModel));
}
try
{
// Note WhenAll instead of WaitAll
// Note await
await Task.WhenAll(tasks);
}
catch (Exception ex) // <- Note plain exception, not AggregatedException
{
...
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