如何在postgres中过滤json的嵌套键值

Question

我在 PostgreSQL 有一张桌子

CREATE TABLE IF NOT EXISTS account_details
(
    account_id integer,
    condition json
)

这张表中的数据是

帐户ID	状况
1个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[35,20,5,6]}}}]
2个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[1,4,2,3]}}}]
3个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[5]}}}]
4个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[1,2,3,5]}}}]
5个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[3,4]}}}]
6个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[4]}}}]
7	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[3]}}}]

我需要获取rootcompanyid中存在的部分值

请指导我如何过滤嵌套的 JSON 数据

预计 Output

情况1

每当我将输入 rootcompanyid = 5 传递给下面的查询时，它应该过滤掉 account_id 1,3 和 4 的详细信息

SELECT *
  FROM account_details
 WHERE ((condition->0->>'conditions')::json->>'rootcompanyid')::json->>'$in' = 5;

帐户ID	状况
1个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[35,20, 5 ,6]}}}]
3个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[ 5 ]}}}]
4个	[{“action”：“read”，“subject”：“rootcompany”，“conditions”：{“rootcompanyid”：{“$in”：[ 1,2,3,5 ]}}}]

案例：2

每当我将输入 rootcompanyid = 3,4 传递给下面的查询时，它应该过滤掉 account_id 2,4,5,6 和 7 的详细信息

SELECT *
  FROM account_details
 WHERE ((condition->0->>'conditions')::json->>'rootcompanyid')::json->>'$in' = 3,4;

帐户ID	状况
2个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[1, 4 ,2, 3 ]}}}]
4个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[1,2, 3 ,5]}}}]
5个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[ 3 , 4 ]}}}]
6个	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[ 4 ]}}}]
7	[{"action":"read","subject":"rootcompany","conditions":{"rootcompanyid":{"$in":[ 3 ]}}}]

请给我最好的解决方案来过滤部分和匹配的JSON格式的 rootcompanyid

Answer 1

您需要比较嵌套的json中的元素。 这是一个例子：

SELECT *
  FROM account_details
 WHERE ((condition->0->>'conditions')::json->>'rootcompanyid')::json->>'$in' = '[35,20,5,6]';

condition->0 - 数组的第一个元素

->>'conditions')::json - 从数组的第一个元素中提取conditions

->>'rootcompanyid')::json - 从conditions中提取rootcompanyid

::json->>'$in' - 从rootcompanyid （ rootcompanyid的 id）中提取$in

按动作搜索：

SELECT *
  FROM account_details
 WHERE condition->0->>'action' = 'read';

更新

要在json array中搜索特定id ，您可以使用@>运算符：

SELECT *
  FROM account_details
 WHERE ((((condition->0->>'conditions')::json->>'rootcompanyid')::json->>'$in')::jsonb) @> '[3,1]'::jsonb

或者LIKE ：

SELECT *
  FROM account_details
 WHERE ((condition->0->>'conditions')::json->>'rootcompanyid')::json->>'$in' LIKE '%5%';

更新 v2

您可以使用json_array_elements_text + exists ：

WITH parsed_conditions AS (
    SELECT account_id,
           json_array_elements_text(
               (((condition -> 0 ->> 'conditions')::json ->> 'rootcompanyid')::json ->>'$in')::json
           ) AS json_id
      FROM account_details
)

SELECT *
  FROM account_details AS a
 WHERE exists(
    SELECT DISTINCT account_id
      FROM parsed_conditions
     WHERE json_id IN ('3', '1')
       AND parsed_condidtions.account_id = a.account_id
);