[英]Zend_Db_Table subquery
我有一些SQL,我想与ZendFW一起使用,但我无法让它工作,这让我发疯。 我通过此查询得到了正确的结果:
SELECT DISTINCT e.festival_id FROM entries AS e, mail_log as m
WHERE e.status = 1
AND e.festival_id
NOT IN (SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id)
帮助将不胜感激。 干杯:)
戈兰的答案是最好的答案。 但是如果你想要一个zend_db_table样式的查询,这将是另一种选择:
$sql = $table->select()
->setIntegrityCheck(false)
->from('entries', new Zend_Db_Expr('DISTINCT festival'))
->where('status = ?', 1)
->where('festival_id NOT IN (?)',new Zend_Db_Expr("SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id"));
我不确定Zend_Db_Table是否能够处理子查询。
为什么需要使用Zend_Db_Table?
您可以使用Zend_Db :: query()直接执行查询。
$db = Zend_Db_Table::getDefaultAdapter();
$db->query("SELECT DISTINCT e.festival_id FROM entries AS e, mail_log as m
WHERE e.status = 1
AND e.festival_id
NOT IN (SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id)
");
就我而言,这有效:
$subselect = $db->select()
->from(array('u1' => 'users'), 'departmentId')
->joinInner(array('d' => 'demand'), 'u1.userId = d.adminId', null)
->where('d.demandId = ?', $demand->getId());
$select2 = $db->select()
->from(array('u' => 'users'))
->where('u.departmentId = ?', $subselect);
结果如下:
SELECT `u`.* FROM `users` AS `u` WHERE u.departmentId = (SELECT `u1`.`departmentId` FROM `users` AS `u1` INNER JOIN `demand` AS `d` ON u1.userId = d.adminId WHERE d.demandId = '1')
我也试试你sql.This是我的代码。
$select = $db->select()
->from(array('e' => ' entries'), array('festival_id'))
->distinct(true)
->where('e.status =?', 1)
->where('e.festival_id NOT IN (SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id)')
->setIntegrityCheck(false);
我认为这段代码比其他代码更具可读性和简单性。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.