正则表达式以零长度的行开始，并在Java中跨行继续

Question

我想匹配以下内容：零长度的行，匹配持续跨非零长度的行，直到在一行中匹配特定的字符串为止。 例如：比赛从零长度线开始，一直持续到到达STOP：

Some random text I don't care about

The match starts at the beginning of this line
The match continues across this line
The match stops here STOP more
text I don't care about

有什么建议么？

谢谢

Answer 1

应该这样做：

(?ms)^[ \t]*+$\s*+((?:(?!STOP).)*+)

一些演示：

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main { 
    public static void main(String[] args) {
        String text = "Some random text I don't care about"      + "\n" +
                ""                                               + "\n" +
                "The match starts at the beginning of this line" + "\n" +
                "The match continues across this line"           + "\n" +
                "The match stops here STOP more"                 + "\n" +
                "don't care about"                               + "\n" +
                ""                                               + "\n" +
                ""                                               + "\n" +
                ""                                               + "\n" +
                "foo"                                            + "\n" +
                "barSTOP"                                        + "\n" +
                "text I don't care about";
        Matcher m = Pattern.compile("(?ms)^[ \t]*+$\\s*+(?:(?!STOP).)*+").matcher(text);
        while(m.find()) {
            System.out.println("match ->"+m.group()+"<-");
        }
    }
}

将输出：

match ->
The match starts at the beginning of this line
The match continues across this line
The match stops here <-
match ->


foo
bar<-

一个小解释：

(?ms)               # enable mutli-line and dot-all
^[ \t]*+$           # match and empty line
\s*+                # match the line break
(                   # start group 1
  (?:(?!STOP).)     #   if the string 'STOP' cannot be seen, match any character
  *+                #   match the previous zero or more times (possessively)
)                   # stop group 1

Answer 2

确保设置“匹配多行”标志，表达式为"\\\\n(\\\\n.*STOP)" 。 第一个（也是唯一一个）匹配组产生您的结果。 在DOS和Windows系统上，使用"\\\\r\\\\n"代替"\\\\n" 。

Answer 3

(?ms)^$(.+)STOP