[英]Is there a way to serialize a c# class to xml without put attributes on the class?
[英]Easier way to serialize C# class as XML text
在尝试回答另一个问题时,我将 C# 对象序列化为 XML 字符串。 这出奇地难; 这是我能想到的最短的代码片段:
var yourList = new List<int>() { 1, 2, 3 };
var ms = new MemoryStream();
var xtw = new XmlTextWriter(ms, Encoding.UTF8);
var xs = new XmlSerializer(yourList.GetType());
xs.Serialize(xtw, yourList);
var encoding = new UTF8Encoding();
string xmlEncodedList = encoding.GetString(ms.GetBuffer());
结果没问题:
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfInt
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<int>1</int>
<int>2</int>
<int>3</int>
</ArrayOfInt>
但是这个片段比我想象的更复杂。 我不敢相信您必须了解这个简单任务的编码和 MemoryStream。
是否有更短的方法将对象序列化为 XML 字符串?
短一点:-)
var yourList = new List<int>() { 1, 2, 3 };
using (var writer = new StringWriter())
{
new XmlSerializer(yourList.GetType()).Serialize(writer, yourList);
var xmlEncodedList = writer.GetStringBuilder().ToString();
}
尽管这种先前的方法存在一个值得指出的缺陷。 当我们使用StringWriter 时,它将生成一个utf-16
标头,因此它不完全等同于您的代码。 要获得utf-8
标头,我们应该使用MemoryStream和XmlWriter ,这是额外的一行代码:
var yourList = new List<int>() { 1, 2, 3 };
using (var stream = new MemoryStream())
{
using (var writer = XmlWriter.Create(stream))
{
new XmlSerializer(yourList.GetType()).Serialize(writer, yourList);
var xmlEncodedList = Encoding.UTF8.GetString(stream.ToArray());
}
}
简单地说,如果你想使用 UTF8 编码,那么就这样做
public class StringWriterUtf8 : System.IO.StringWriter
{
public override Encoding Encoding
{
get
{
return Encoding.UTF8;
}
}
}
然后像这样使用 StringWriterUtf8 读取 StringWriter
using (StringWriterUtf8 textWriter = new StringWriterUtf8())
{
serializer.Serialize(textWriter, tr, ns);
xmlText = textWriter.ToString();
}
编写扩展方法或包装类/函数来封装代码段。
您不需要MemoryStream
,只需使用StringWriter
:
var yourList = new List<int>() { 1, 2, 3 };
using (StringWriter sw = new StringWriter())
{
var xs = new XmlSerializer(yourList.GetType());
xs.Serialize(sw, yourList);
string xmlEncodedList = sw.ToString();
}
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