繁体   English   中英

使用C#中的XSLT将XML转换为HTML的最简单方法?

[英]Simplest way to transform XML to HTML with XSLT in C#?

XSLT新手问题:请填写下面的C#代码片段中的空白:

public static string TransformXMLToHTML(string inputXml, string xsltString) {
  // insert code here to apply the transform specified by xsltString to inputXml 
  // and return the resultant HTML string.
  // You may assume that the xslt output type is HTML.
}

谢谢!

怎么样:

public static string TransformXMLToHTML(string inputXml, string xsltString)
{
    XslCompiledTransform transform = new XslCompiledTransform();
    using(XmlReader reader = XmlReader.Create(new StringReader(xsltString))) {
        transform.Load(reader);
    }
    StringWriter results = new StringWriter();
    using(XmlReader reader = XmlReader.Create(new StringReader(inputXml))) {
        transform.Transform(reader, null, results);
    }
    return results.ToString();
}

请注意,理想情况下,您将缓存并重新使用XslCompiledTransform - 或者可能使用XslTransform (但它被标记为已弃用)。

只是为了好玩,一个稍微不那么优雅的版本实现了Marc建议的缓存:

    public static string TransformXMLToHTML(string inputXml, string xsltString)
    {
        XslCompiledTransform transform = GetAndCacheTransform(xsltString);
        StringWriter results = new StringWriter();
        using (XmlReader reader = XmlReader.Create(new StringReader(inputXml)))
        {
            transform.Transform(reader, null, results);
        }
        return results.ToString();
    }

    private static Dictionary<String, XslCompiledTransform> cachedTransforms = new Dictionary<string, XslCompiledTransform>();
    private static XslCompiledTransform GetAndCacheTransform(String xslt)
    {
        XslCompiledTransform transform;
        if (!cachedTransforms.TryGetValue(xslt, out transform))
        {
            transform = new XslCompiledTransform();
            using (XmlReader reader = XmlReader.Create(new StringReader(xslt)))
            {
                transform.Load(reader);
            }
            cachedTransforms.Add(xslt, transform);
        }
        return transform;
    }

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM