[英]Easiest Way to get id or link and updated date from a RSS feed?
我尝试使用linq,但失败了,因为我没有xml知识。
从rss提要中获取ID或链接并进行更新的最简单方法是什么? (示例供稿-> https://stackoverflow.com/feeds/question/1926343 )
我不知道如何跳过所有元素直到第一个入口元素。 我也不知道如何从入口元素中的每个元素中提取每个链接和数据
这是如何执行此操作的最小示例:
var url = "http://stackoverflow.com/feeds/question/1926343";
var rss = new WebClient().DownloadString(url);
var doc = XDocument.Parse(rss);
var mgr = new XmlNamespaceManager(new NameTable());
var ns = "http://www.w3.org/2005/Atom";
mgr.AddNamespace("atom", ns);
foreach (var entry in doc.XPathSelectElements("/atom:feed/atom:entry", mgr))
{
var id = entry.Element(XName.Get("id", ns)).Value;
var link = entry.Element(XName.Get("link", ns)).Attribute("href").Value;
var updated = entry.Element(XName.Get("updated", ns)).Value;
Console.WriteLine(id);
Console.WriteLine("\tLink: " + link);
Console.WriteLine("\tUpdated: " + updated);
}
这是它生成的输出:
http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c
Link: http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c
Updated: 2009-12-18T05:21:53Z
http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926359#1926359
Link: http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926359#1926359
Updated: 2009-12-18T04:56:01Z
http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926361#1926361
Link: http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926361#1926361
Updated: 2009-12-18T04:56:06Z
http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926365#1926365
Link: http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926365#1926365
Updated: 2009-12-18T04:58:08Z
http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926446#1926446
Link: http://stackoverflow.com/questions/1926343/alternative-to-thead-sleep-in-c/1926446#1926446
Updated: 2009-12-18T05:21:53Z
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