[英]Top Values in a Query by Group
我知道如何获得最高价值,但遇到一些非常简单的问题。
我有一张学生桌。 它具有:
我想要一个查询或报告,以显示每个年级单圈最多的前两个孩子。
MySQL没有任何排名功能,但是它允许创建和更新变量:
SELECT x.grade,
x.name,
x.numberoflaps
FROM (SELECT s.grade,
s.name,
s.numberoflaps,
CASE
WHEN @grade != s.grade THEN @rownum := 1
ELSE @rownum := @rownum + 1
END AS rank,
@grade := s.grade
FROM STUDENTS s,
(SELECT @rownum := 0, @grade := NULL) r
ORDER BY s.grade, s.numberoflaps DESC) x
WHERE x.rank <= 2
ORDER BY x.grade, x.rank
子查询中的ORDER BY
很重要,否则排名将无法正确执行。
使用CTE:
WITH laps AS (
SELECT s.grade,
s.name,
s.numberoflaps,
ROW_NUMBER() OVER (PARTITION BY grade ORDER BY numberoflaps DESC) AS rank
FROM STUDENTS s)
SELECT l.grade,
l.name,
l.numberoflaps
FROM laps l
WHERE l.rank <= 2
ORDER BY l.grade, l.numberoflaps DESC
相当于非CTE:
SELECT l.grade,
l.name,
l.numberoflaps
FROM (SELECT s.grade,
s.name,
s.numberoflaps,
ROW_NUMBER() OVER (PARTITION BY grade ORDER BY numberoflaps DESC) AS rank
FROM STUDENTS s) l
WHERE l.rank <= 2
ORDER BY l.grade, l.numberoflaps DESC
Oracle在9i中获得了排名功能; 对于SQL Server,是2005年。
SQL Server 2005+版本如下所示:
;WITH Laps_CTE AS
(
SELECT
grade, name, numberoflaps,
ROW_NUMBER() OVER (
PARTITION BY grade
ORDER BY numberoflaps DESC
) AS RowNum
FROM students
)
SELECT grade, name, numberoflaps
FROM Laps_CTE
WHERE RowNum <= 2
如果那不是您的方言,请告诉我们是什么。
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