根据用户的时间设置问候语（早上好，下午好......）

Question

谁能根据用户的时间设置推断出如何实现基本的“晚上好”或“早上好”？

也许 PHP 会获取服务器时间，但我希望使用基于时间的适当问候语来迎接站点访问者，该问候语考虑了他们一天中的时间。

EG：早上好，晚上好，下午好。

Answer 1

它基于日期对象的.getHours() 。 使用 javascript 的 Date 对象将自动使用用户的本地时间，而不是服务器时间：

var now = new Date();
alert( now.getHours() );

几个条件检查，你在做生意。 例如，下面是一个非常简单易懂的例子：

var now = new Date();
var hrs = now.getHours();
var msg = "";

if (hrs >  0) msg = "Mornin' Sunshine!"; // REALLY early
if (hrs >  6) msg = "Good morning";      // After 6am
if (hrs > 12) msg = "Good afternoon";    // After 12pm
if (hrs > 17) msg = "Good evening";      // After 5pm
if (hrs > 22) msg = "Go to bed!";        // After 10pm

alert(msg);

现在是凌晨 2 点 56 分，所以我看到了“Mornin' Sunshine！” 当我运行这个。 您可以使用此在线演示测试您自己的本地时间： http : //jsbin.com/aguyo3/edit

Answer 2

<?php
// I'm India so my timezone is Asia/Calcutta
date_default_timezone_set('Asia/Calcutta');

// 24-hour format of an hour without leading zeros (0 through 23)
$Hour = date('G');

if ( $Hour >= 5 && $Hour <= 11 ) {
    echo "Good Morning";
} else if ( $Hour >= 12 && $Hour <= 18 ) {
    echo "Good Afternoon";
} else if ( $Hour >= 19 || $Hour <= 4 ) {
    echo "Good Evening";
}
?>

有关日期的更多信息，请参阅function.date 。 我希望这将有所帮助。

Answer 3

<?php
    /* This sets the $time variable to the current hour in the 24 hour clock format */
    $time = date("H");
    /* Set the $timezone variable to become the current timezone */
    $timezone = date("e");
    /* If the time is less than 1200 hours, show good morning */
    if ($time < "12") {
        echo "Good morning";
    } else
    /* If the time is grater than or equal to 1200 hours, but less than 1700 hours, so good afternoon */
    if ($time >= "12" && $time < "17") {
        echo "Good afternoon";
    } else
    /* Should the time be between or equal to 1700 and 1900 hours, show good evening */
    if ($time >= "17" && $time < "19") {
        echo "Good evening";
    } else
    /* Finally, show good night if the time is greater than or equal to 1900 hours */
    if ($time >= "19") {
        echo "Good night";
    }
    ?>

Answer 4

$hour      = date('H');

if ($hour >= 20) {
    $greetings = "Good Night";
} elseif ($hour > 17) {
   $greetings = "Good Evening";
} elseif ($hour > 11) {
    $greetings = "Good Afternoon";
} elseif ($hour < 12) {
   $greetings = "Good Morning";
}
echo $greetings;

Answer 5

const now = new Date().getHours();

switch (true) {
    case (now<=12): console.log("Good Morning");break;
    case (now>12 && now<16): console.log("Good Afternnon");break;
    case (now>=16 && now<20): console.log("Good Evening");break;
    case (now>=20 && now<=24): console.log("Good Night");break;}

此代码基于 JavaScript，希望对您有所帮助。

Answer 6

function greeting_msg() {
    $hour = date('H');
    if ($hour >= 18) {
       $greeting = "Good Evening";
    } elseif ($hour >= 12) {
        $greeting = "Good Afternoon";
    } elseif ($hour < 12) {
       $greeting = "Good Morning";
    }
    return $greeting;
}