SQL：选择表中的所有内容而不是子查询中的所有内容？

Question

该查询似乎运行良好：

-- Every supplier that produces some red or green part
SELECT Suppliers.sid
FROM Suppliers, Catalog, Parts
WHERE Suppliers.sid = Catalog.sid 
    AND Catalog.pid = Parts.pid
    AND (Parts.color = "red" OR Parts.color = "green");

为了进行检查，我想查看该查询不会返回的每个SID，以确保它们不会产生绿色或红色部分。 我怎样才能做到这一点？

这似乎不起作用：

SELECT Parts.color
FROM Suppliers, Catalog, Parts
WHERE Suppliers.sid NOT IN (    
    SELECT Suppliers.sid, Parts.color
    FROM Suppliers, Catalog, Parts
    WHERE Suppliers.sid = Catalog.sid 
        AND Catalog.pid = Parts.pid
        AND (Parts.color = "red" OR Parts.color = "green")
    );

MySQL错误：

错误1241（21000）：操作数应包含1列

解决这个问题的正确方法是什么？

这是用于创建正在使用的表的SQL：

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL';

CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ;
USE `mydb`;

-- -----------------------------------------------------
-- Table `mydb`.`Suppliers`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `mydb`.`Suppliers` (
  `sid` INT NOT NULL ,
  `sname` VARCHAR(45) NULL ,
  `address` VARCHAR(45) NULL ,
  PRIMARY KEY (`sid`) )
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `mydb`.`Parts`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `mydb`.`Parts` (
  `pid` INT NOT NULL ,
  `pname` VARCHAR(45) NULL ,
  `color` VARCHAR(45) NULL ,
  PRIMARY KEY (`pid`) )
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `mydb`.`Catalog`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `mydb`.`Catalog` (
  `cost` INT NULL ,
  `pid` INT NOT NULL ,
  `sid` INT NOT NULL ,
  PRIMARY KEY (`pid`, `sid`) ,
  INDEX `fk_Catalog_Parts1` (`pid` ASC) ,
  INDEX `fk_Catalog_Suppliers1` (`sid` ASC) ,
  CONSTRAINT `fk_Catalog_Parts1`
    FOREIGN KEY (`pid` )
    REFERENCES `mydb`.`Parts` (`pid` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Catalog_Suppliers1`
    FOREIGN KEY (`sid` )
    REFERENCES `mydb`.`Suppliers` (`sid` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;



SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

Answer 1

不能完全知道您的意思，但我发现有几处错误。 首先删除子查询中的第二列，这是不必要的：

SELECT Parts.color 
FROM Suppliers, Catalog, Parts 
WHERE Suppliers.sid NOT IN (     
    SELECT Suppliers.sid    FROM Suppliers, Catalog, Parts 
    WHERE Suppliers.sid = Catalog.sid  
        AND Catalog.pid = Parts.pid 
        AND (Parts.color = "red" OR Parts.color = "green") 
    ); 

最后，您似乎有一个交叉连接，我想您不想这样做。 这是为什么不应该使用隐式联接的经典示例。 看看是否可以更好地工作：

SELECT Parts.color 
FROM Suppliers 
JOIN Catalog  on Suppliers.sid = Catalog.sid  
JOIN  Parts on Catalog.pid = Parts.pid 
WHERE Suppliers.sid NOT IN (     
    SELECT Suppliers.sid
    FROM  Suppliers 
    JOIN Catalog  on Suppliers.sid = Catalog.sid  
    JOIN  Parts on Catalog.pid = Parts.pid 
       WHERE (Parts.color = "red" OR Parts.color = "green") 
    ); 

Answer 2

更改您的子查询以返回一列。

旧子查询

SELECT Suppliers.sid, Parts.color
    FROM Suppliers, Catalog, Parts
    WHERE Suppliers.sid = Catalog.sid 
        AND Catalog.pid = Parts.pid
        AND (Parts.color = "red" OR Parts.color = "green"

新子查询

SELECT Suppliers.sid
    FROM Suppliers, Catalog, Parts
    WHERE Suppliers.sid = Catalog.sid 
        AND Catalog.pid = Parts.pid
        AND (Parts.color = "red" OR Parts.color = "green"

Answer 3

内部选择仅需要返回ID

删除： , Parts.color

SELECT Parts.color
FROM Suppliers, Catalog, Parts
WHERE Suppliers.sid NOT IN (    
SELECT Suppliers.sid
FROM Suppliers, Catalog, Parts
WHERE Suppliers.sid = Catalog.sid 
    AND Catalog.pid = Parts.pid
    AND (Parts.color = "red" OR Parts.color = "green")
);