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[英]What could the following gcc compilation error mean and why does it have a part that looks like the encoding is corrupted?
[英]I have a following gcc compilation warning
symbol.h:179: note: expected ‘uintptr_t *’ but argument is of type ‘PRECEDENCE’
相应的代码是:
176 void symbol_SetCount(SYMBOL, unsigned long);
177 unsigned long symbol_GetCount(SYMBOL);
178
179 size_t symbol_Ordering(uintptr_t*, SYMBOL);
180
181 void symbol_CheckIndexInRange(int);
182 void symbol_CheckNoVariable(SYMBOL);
SYMBOL定义为:
typedef size_t SYMBOL
任何努力将不胜感激。
PRECEDENCE已修改为:
typedef int *PRECEDENCE;
int symbol_Ordering(PRECEDENCE, SYMBOL);
这是symbol_Ordering的一些其他信息:
if (symbol_Equal(propSymbol, eml_Id()))
{ /* Arguments should be nil, propositional */
symbol_SetOrdering(Precedence, fol_Equality(), symbol_Ordering(Precedence, eml_Id()));
return eml_RplacWithOpAndArgs(Atom, fol_Equality(), Args)}
int symbol_ORDERING;
int symbol_GetIncreasedOrderingCounter(void)
{return symbol_ORDERING ++; }
static __inline__ BOOL symbol_PrecedenceGreater(PRECEDENCE P, SYMBOL S1, SYMBOL S2)
{
return symbol_Ordering((uintptr_t*)P, S1) < symbol_Ordering((uintptr_t*)P, S2);
}
size_t symbol_Ordering(uintptr_t*, SYMBOL);
似乎您有多个symbol_Ordering
声明-一个声明为uintptr_t*
,另一个声明为int*
。 uintptr_t*
和int*
的类型不同(一个是带符号的,一个是无符号的),所以不要那样做。 使类型匹配。
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