如何在SQL Server 2005中进行sql表的尴尬转移？

Question

我必须从SQL Server旋转给定的表，但正常的数据透视表不起作用（据我所知）。 那么有人知道如何将表格旋转成所需的格式吗？

只是为了使问题更复杂，给定标签的列表可能会有所不同，并且可能会在任何给定时间出现新的标签名称。

鉴于数据

ID |  Label          |  Numerator  |  Denominator  |  Ratio 
---+-----------------+-------------+---------------+--------
1  |  LabelNameOne   |  41         |  10           |  4,1   
1  |  LabelNameTwo   |  0          |  0            |  0     
1  |  LabelNameThree |  21         |  10           |  2,1   
1  |  LabelNameFour  |  15         |  10           |  1,5   
2  |  LabelNameOne   |  19         |  19           |  1     
2  |  LabelNameTwo   |  0          |  0            |  0     
2  |  LabelNameThree |  15         |  16           |  0,9375
2  |  LabelNameFive  |  19         |  19           |  1     
2  |  LabelNameSix   |  17         |  17           |  1     
3  |  LabelNameOne   |  12         |  12           |  1     
3  |  LabelNameTwo   |  0          |  0            |  0     
3  |  LabelNameThree |  11         |  12           |  0,9167
3  |  LabelNameFour  |  12         |  12           |  1     
3  |  LabelNameSix   |  0          |  1            |  0     

想要结果

ID | ValueType   | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix
---+-------------+--------------+--------------+----------------+---------------+---------------+--------------
1  | Numerator   | 41           | 0            | 21             | 15            |               |              
1  | Denominator | 10           | 0            | 10             | 10            |               |              
1  | Ratio       | 4,1          | 0            | 2,1            | 1,5           |               |              
2  | Numerator   | 19           | 0            | 15             |               | 19            | 17           
2  | Denominator | 19           | 0            | 16             |               | 19            | 17           
2  | Ratio       | 1            | 0            | 0,9375         |               | 1             | 1            
3  | Numerator   | 12           | 0            | 11             | 12            |               | 0            
3  | Denominator | 12           | 0            | 12             | 12            |               | 1            
3  | Ratio       | 1            | 0            | 0,9167         | 1             |               | 0            

Answer 1

这应该可以解决你的问题。 它真的是一个UNPIVOT和一个PIVOT。 请注意，您必须符合您的数据，因为UNPIVOT将所有数据放在同一列中。

请注意，我必须在内部动态SQL中重新创建/重新填充表变量 - 通常在处理永久表时不需要这样做。

SET NOCOUNT ON ;

DECLARE @pivot_cols AS varchar(max) ;
DECLARE @src AS TABLE
    (
     ID int NOT NULL
    ,Label varchar(14) NOT NULL
    ,Numerator int NOT NULL
    ,Denominator int NOT NULL
    ,Ratio decimal(5, 4) NOT NULL
    ) ;

DECLARE @label_order AS TABLE
    (
     Label varchar(14) NOT NULL
    ,Sort int NOT NULL
    )

INSERT  INTO @src
VALUES  (1, 'LabelNameOne', 41, 10, 4.1) ;
INSERT  INTO @src
VALUES  (1, 'LabelNameTwo', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (1, 'LabelNameThree', 21, 10, 2.1) ;
INSERT  INTO @src
VALUES  (1, 'LabelNameFour', 15, 10, 1.5) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameOne', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameTwo', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameThree', 15, 16, 0.9375) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameFive', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameSix', 17, 17, 1) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameOne', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameTwo', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameThree', 11, 12, 0.9167) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameFour', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameSix', 0, 1, 0) ;

INSERT  INTO @label_order
VALUES  ('LabelNameOne', 1) ;
INSERT  INTO @label_order
VALUES  ('LabelNameTwo', 2) ;
INSERT  INTO @label_order
VALUES  ('LabelNameThree', 3) ;
INSERT  INTO @label_order
VALUES  ('LabelNameFour', 4) ;
INSERT  INTO @label_order
VALUES  ('LabelNameFive', 5) ;
INSERT  INTO @label_order
VALUES  ('LabelNameSix', 6) ;

WITH    Labels
          AS (
              SELECT  DISTINCT
                        src.Label
                       ,ISNULL(label_order.Sort, 0) AS Sort
              FROM      @src AS src
              LEFT JOIN @label_order AS label_order
                        ON src.label = label_order.label
             )
    SELECT  @pivot_cols = COALESCE(@pivot_cols + ',', '') + QUOTENAME(Label, '[')
    FROM    Labels
    ORDER BY Sort
           ,Label ;

DECLARE @template AS varchar(max) ;

SET @template = '
DECLARE @src AS TABLE
    (
     ID int NOT NULL
    ,Label varchar(14) NOT NULL
    ,Numerator int NOT NULL
    ,Denominator int NOT NULL
    ,Ratio decimal(5, 4) NOT NULL
    ) ;

INSERT  INTO @src
VALUES  (1, ''LabelNameOne'', 41, 10, 4.1) ;
INSERT  INTO @src
VALUES  (1, ''LabelNameTwo'', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (1, ''LabelNameThree'', 21, 10, 2.1) ;
INSERT  INTO @src
VALUES  (1, ''LabelNameFour'', 15, 10, 1.5) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameOne'', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameTwo'', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameThree'', 15, 16, 0.9375) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameFive'', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameSix'', 17, 17, 1) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameOne'', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameTwo'', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameThree'', 11, 12, 0.9167) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameFour'', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameSix'', 0, 1, 0) ;

WITH    src_conformed
          AS (
              SELECT    ID
                       ,Label
                       ,CAST (Numerator AS decimal(10, 4)) AS Numerator
                       ,CAST (Denominator AS decimal(10, 4)) AS Denominator
                       ,CAST (Ratio AS decimal(10, 4)) AS Ratio
              FROM      @src
             ),
        UNPIVOTED
          AS (
              SELECT    *
              FROM      src_conformed UNPIVOT ( Val FOR Col IN (Numerator, Denominator, Ratio) ) AS unpvt
             )
    SELECT  *
    FROM    UNPIVOTED PIVOT ( SUM(Val) FOR Label IN ({@pivot_cols}) ) AS pvt
    ORDER BY ID
           ,Col ;' ;

SET @template = REPLACE(@template, '{@pivot_cols}', @pivot_cols) ;

EXEC (@template) ;

Answer 2

select
id,
'Numerator' as ValueType,
case when label = labelNameOne then Numerator else 0 end as LabelNameOne,
case when label = labelNameTwo then Numerator else 0 end as LabelNameTwo,
case when label = labelNameTree then Numerator else 0 end as LabelNameTree,
case when label = labelNameFour then Numerator else 0 end as LabelNameFour,
case when label = labelNameFive then Numerator else 0 end as LabelNameFive,
case when label = labelNameSix then Numerator else 0 end as LabelNameSix

union All

...与Denominator的类似查询...

union all

...与Ratio的类似查询...

Answer 3

您寻求的是动态交叉表。 简短的回答是，如果没有一些不稳定的动态SQL，它就无法在T-SQL中完成。 霍伊尔的答案是你应该在报告工具或中间层中转动数据。