使用zxing进行二维码编解码

Question

好的，所以我要抓住这里有人以前使用过 zxing 的机会。 我正在开发一个 Java 应用程序，它需要做的一件事是将数据的字节数组编码为二维码，然后稍后对其进行解码。

这是我的编码器的示例：

byte[] b = {0x48, 0x45, 0x4C, 0x4C, 0x4F};
//convert the byte array into a UTF-8 string
String data;
try {
    data = new String(b, "UTF8");
}
catch (UnsupportedEncodingException e) {
 //the program shouldn't be able to get here
 return;
}

//get a byte matrix for the data
ByteMatrix matrix;
com.google.zxing.Writer writer = new QRCodeWriter();
try {
 matrix = writer.encode(data, com.google.zxing.BarcodeFormat.QR_CODE, width, height);
}
catch (com.google.zxing.WriterException e) {
 //exit the method
 return;
}

//generate an image from the byte matrix
int width = matrix.getWidth(); 
int height = matrix.getHeight(); 

byte[][] array = matrix.getArray();

//create buffered image to draw to
BufferedImage image = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);

//iterate through the matrix and draw the pixels to the image
for (int y = 0; y < height; y++) { 
 for (int x = 0; x < width; x++) { 
  int grayValue = array[y][x] & 0xff; 
  image.setRGB(x, y, (grayValue == 0 ? 0 : 0xFFFFFF));
 }
}

//write the image to the output stream
ImageIO.write(image, "png", outputStream);

此代码中的起始字节数组仅用于测试它。 实际的字节数据会有所不同。

这是我的解码器的样子：

//get the data from the input stream
BufferedImage image = ImageIO.read(inputStream);

//convert the image to a binary bitmap source
LuminanceSource source = new BufferedImageLuminanceSource(image);
BinaryBitmap bitmap = new BinaryBitmap(new HybridBinarizer(source));

//decode the barcode
QRCodeReader reader = new QRCodeReader();

Result result;
try {
 result = reader.decode(bitmap, hints);
} catch (ReaderException e) {
 //the data is improperly formatted
 throw new MCCDatabaseMismatchException();
}

byte[] b = result.getRawBytes();
System.out.println(ByteHelper.convertUnsignedBytesToHexString(result.getText().getBytes("UTF8")));
System.out.println(ByteHelper.convertUnsignedBytesToHexString(b));

convertUnsignedBytesToHexString(byte)是一种将字节数组转换为十六进制字符字符串的方法。

当我尝试将这两个代码块一起运行时，这是输出：

48454c4c4f
202b0b78cc00ec11ec11ec11ec11ec11ec11ec

显然文本正在被编码，但数据的实际字节完全关闭。 任何帮助将不胜感激。

Answer 1

因此，为了给不想花两天时间在互联网上搜索以解决这个问题的任何人的未来参考，当您将字节数组编码为二维码时，您必须使用ISO-8859-1字符集，而不是UTF-8 .

Answer 2

这是我的工作示例 Java 代码，使用 ZXing 和 UTF-8 编码对二维码进行编码，请注意：您需要将路径和 utf8 数据更改为您的路径和语言字符

package com.mypackage.qr;

import java.io.File;
import java.io.IOException;
import java.io.UnsupportedEncodingException;
import java.nio.ByteBuffer;
import java.nio.CharBuffer;
import java.nio.charset.CharacterCodingException;
import java.nio.charset.Charset;
import java.nio.charset.CharsetEncoder;
import java.util.Hashtable;

import com.google.zxing.EncodeHintType;
import com.google.zxing.MultiFormatWriter;
import com.google.zxing.client.j2se.MatrixToImageWriter;
import com.google.zxing.common.*;

public class CreateQR {

public static void main(String[] args)
{
    Charset charset = Charset.forName("UTF-8");
    CharsetEncoder encoder = charset.newEncoder();
    byte[] b = null;
    try {
        // Convert a string to UTF-8 bytes in a ByteBuffer
        ByteBuffer bbuf = encoder.encode(CharBuffer.wrap("utf 8 characters - i used hebrew, but you should write some of your own language characters"));
        b = bbuf.array();
    } catch (CharacterCodingException e) {
        System.out.println(e.getMessage());
    }

    String data;
    try {
        data = new String(b, "UTF-8");
        // get a byte matrix for the data
        BitMatrix matrix = null;
        int h = 100;
        int w = 100;
        com.google.zxing.Writer writer = new MultiFormatWriter();
        try {
            Hashtable<EncodeHintType, String> hints = new Hashtable<EncodeHintType, String>(2);
            hints.put(EncodeHintType.CHARACTER_SET, "UTF-8");
            matrix = writer.encode(data,
            com.google.zxing.BarcodeFormat.QR_CODE, w, h, hints);
        } catch (com.google.zxing.WriterException e) {
            System.out.println(e.getMessage());
        }

        // change this path to match yours (this is my mac home folder, you can use: c:\\qr_png.png if you are on windows)
                String filePath = "/Users/shaybc/Desktop/OutlookQR/qr_png.png";
        File file = new File(filePath);
        try {
            MatrixToImageWriter.writeToFile(matrix, "PNG", file);
            System.out.println("printing to " + file.getAbsolutePath());
        } catch (IOException e) {
            System.out.println(e.getMessage());
        }
    } catch (UnsupportedEncodingException e) {
        System.out.println(e.getMessage());
    }
}

}

Answer 3

就其价值而言，我的 groovy 尖峰似乎适用于 UTF-8 和 ISO-8859-1 字符编码。 不确定当非 zxing 解码器尝试解码 UTF-8 编码图像时会发生什么……可能因设备而异。

// ------------------------------------------------------------------------------------
// Requires: groovy-1.7.6, jdk1.6.0_03, ./lib with zxing core-1.7.jar, javase-1.7.jar 
// Javadocs: http://zxing.org/w/docs/javadoc/overview-summary.html
// Run with: groovy -cp "./lib/*" zxing.groovy
// ------------------------------------------------------------------------------------

import com.google.zxing.*
import com.google.zxing.common.*
import com.google.zxing.client.j2se.*

import java.awt.image.BufferedImage
import javax.imageio.ImageIO

def class zxing {
    def static main(def args) {
        def filename = "./qrcode.png"
        def data = "This is a test to see if I can encode and decode this data..."
        def charset = "UTF-8" //"ISO-8859-1" 
        def hints = new Hashtable<EncodeHintType, String>([(EncodeHintType.CHARACTER_SET): charset])

        writeQrCode(filename, data, charset, hints, 100, 100)

        assert data == readQrCode(filename, charset, hints)
    }

    def static writeQrCode(def filename, def data, def charset, def hints, def width, def height) {
        BitMatrix matrix = new MultiFormatWriter().encode(new String(data.getBytes(charset), charset), BarcodeFormat.QR_CODE, width, height, hints)
        MatrixToImageWriter.writeToFile(matrix, filename.substring(filename.lastIndexOf('.')+1), new File(filename))
    }

    def static readQrCode(def filename, def charset, def hints) {
        BinaryBitmap binaryBitmap = new BinaryBitmap(new HybridBinarizer(new BufferedImageLuminanceSource(ImageIO.read(new FileInputStream(filename)))))
        Result result = new MultiFormatReader().decode(binaryBitmap, hints)

        result.getText()        
    }

}

Answer 4

也许值得一看QRGen ，它建立在 ZXing 之上并支持 UTF-8 与这种语法：

// if using special characters don't forget to supply the encoding
VCard johnSpecial = new VCard("Jöhn Dɵe")
                        .setAdress("ëåäöƞ Sträät 1, 1234 Döestüwn");
QRCode.from(johnSpecial).withCharset("UTF-8").file();

Answer 5

如果您确实需要对 UTF-8 进行编码，您可以尝试在 unicode 字节顺序标记之前添加。 我不知道对这种方法的支持有多广泛，但 ZXing 至少似乎支持它： http : //code.google.com/p/zxing/issues/detail? id=103

我最近一直在阅读 QR 模式，我想我在其他地方看到过同样的做法，但我没有最迷茫的地方。

Answer 6

我尝试使用 ISO-8859-1，如第一个答案中所述。 编码一切正常，但是当我尝试在解码时使用结果字符串获取字节 [] 时，所有负字节都变成了字符 63（问号）。 以下代码不起作用：

// Encoding works great
byte[] contents = new byte[]{-1};
QRCodeWriter codeWriter = new QRCodeWriter();
BitMatrix bitMatrix = codeWriter.encode(new String(contents, Charset.forName("ISO-8859-1")), BarcodeFormat.QR_CODE, w, h);

// Decodes like this fails
LuminanceSource ls = new BufferedImageLuminanceSource(encodedBufferedImage);
Result result = new QRCodeReader().decode(new BinaryBitmap( new HybridBinarizer(ls)));
byte[] resultBytes = result.getText().getBytes(Charset.forName("ISO-8859-1")); // a byte[] with byte 63 is given
return resultBytes;

看起来很奇怪，因为在一个非常旧的版本（不知道确切）中的 API 有一个方法 thar 工作得很好：

Vector byteSegments = result.getByteSegments();

所以我试图搜索为什么这个方法被删除并意识到有一种方法可以通过元数据获取 ByteSegments。 所以我的解码方法看起来像：

// Decodes like this works perfectly
LuminanceSource ls = new BufferedImageLuminanceSource(encodedBufferedImage);
Result result = new QRCodeReader().decode(new BinaryBitmap( new HybridBinarizer(ls)));
Vector byteSegments = (Vector) result.getResultMetadata().get(ResultMetadataType.BYTE_SEGMENTS);  
int i = 0;
int tam = 0;
for (Object o : byteSegments) {
    byte[] bs = (byte[])o;
    tam += bs.length;
}
byte[] resultBytes = new byte[tam];
i = 0;
for (Object o : byteSegments) {
    byte[] bs = (byte[])o;
    for (byte b : bs) {
        resultBytes[i++] = b;
    }
}
return resultBytes;