[英]Match multiple lines with a regex in C#
我有以下文字:
--------------030805090908050805080502
Content-Type: image/jpeg
Content-Transfer-Encoding: base64
Content-ID: <part16.07030906.00090703@highcontrast.ro>
/9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA
/9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA
QBQH/9k=
--------------030805090908050805080502
Content-Type: image/jpeg
Content-Transfer-Encoding: base64
Content-ID: <part17.07010805.02020809@highcontrast.ro>
/9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA
/9j/4AAQSkZJRgABAgAAZABkAAD/7AARRHVja3kAAQAEAAAARgAA/+4ADkFkb2JlAGTAAAAA
juu41lRHFLufPCAID//Z
--------------030805090908050805080502--
我需要在C#2部分使用Regex:
"--------------030805090908050805080502"
的第一个和第二个出现之间 "--------------030805090908050805080502"
和"--------------030805090908050805080502--"
我试过这个正则表达式:
--------------030805090908050805080502(\r.*)*--------------030805090908050805080502
但在C#中, regex.Matches(...)
仅返回"--------------030805090908050805080502"
。
MatchCollection matches = Regex.Matches( text, @"([-]+\d{24})
(?<Content>.*?)
(?=\1)",
RegexOptions.IgnorePatternWhitespace |
RegexOptions.Singleline );
foreach ( Match match in matches )
{
Console.WriteLine(
string.Format( "match: {0}\n\n",
match.Groups[ "Content" ].Value ) );
}
更新:此表达式将查找两次出现的数字之间的所有匹配。 如果号码必须是特定号码,而不是任何24位数字,请将“\\ d {24}”更改为您要匹配的号码。
你试过斯普利特 :
var str = stringToParse.Split(
new[] { "--------------030805090908050805080502" },
StringSplitOptions.None);
Console.WriteLine(str[1]);
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