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RegEx替换查询以选择Wiki语法

[英]RegEx replace query to pick out wiki syntax

我有一个HTML字符串,我需要从例如HTML中获取“ [Title | http://www.test.com] ”模式

“ dafasdfasdf,adfasd。[测试| http://www.test.com/] adf ddasfasdf [SDAF | http://www.madee.com/] assg广告”

我需要将“ [Title | http://www.test.com] ”替换为“ http://www.test.com/'>Title”。

解决这个问题的最佳途径是什么?

我越来越接近:

string test = "dafasdfasdf adfasd [Test|http://www.test.com/] adf ddasfasdf [SDAF|http://www.madee.com/] assg ad ";
        string p18 = @"(\[.*?|.*?\])";
        MatchCollection mc18 = Regex.Matches(test, p18, RegexOptions.Singleline | RegexOptions.IgnoreCase);
        foreach (Match m in mc18)
        {
            string value = m.Groups[1].Value;
            string fulltag = value.Substring(value.IndexOf("["), value.Length - value.IndexOf("["));
            Console.WriteLine("text=" + fulltag);
        }

必须有一种更干净的方法来获取两个值,例如“ Title”位和url本身。

有什么建议么?

替换模式:

\[([^|]+)\|[^]]*]

有:

$1

简短说明:

\[         # match the character '['
(          # start capture group 1
  [^|]+    #   match any character except '|' and repeat it one or more times
)          # end capture group 1
\|         # match the character '|'
[^]]*      # match any character except ']' and repeat it zero or more times
]          # match the character ']'

AC#演示看起来像:

string test = "dafasdfasdf adfasd [Test|http://www.test.com/] adf ddasfasdf [SDAF|http://www.madee.com/] assg ad ";
string adjusted = Regex.Replace(test, @"\[([^|]+)\|[^]]*]", "$1");

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