繁体   English   中英

SWT Composite构造函数在非null参数上引发IllegalArgumentException

[英]SWT Composite constructor throws IllegalArgumentException on a non-null argument

这段代码(在Scala中)

val contents = {
  assert(mainWindow.detailsPane != null)
  new Composite(mainWindow.detailsPane, SWT.NONE)
}

引发异常:

Exception occurred
java.lang.IllegalArgumentException: Argument not valid
    at org.eclipse.swt.SWT.error(Unknown Source)
    at org.eclipse.swt.SWT.error(Unknown Source)
    at org.eclipse.swt.SWT.error(Unknown Source)
    at org.eclipse.swt.widgets.Widget.error(Unknown Source)
    at org.eclipse.swt.widgets.Widget.checkParent(Unknown Source)
    at org.eclipse.swt.widgets.Widget.<init>(Unknown Source)
    at org.eclipse.swt.widgets.Control.<init>(Unknown Source)
    at org.eclipse.swt.widgets.Scrollable.<init>(Unknown Source)
    at org.eclipse.swt.widgets.Composite.<init>(Unknown Source)
    at main.scala.NodeViewPresenter$NodeViewImpl.<init>(NodeViewPresenter.scala:41)

根据文档 ,仅当父级为null时才应抛出IllegalArgumentException ,但我正在检查这一点。 detailsPaneCTabFolder 为什么会发生这种情况?

在Eclipse论坛上给出的解决方案: detailsPanedetailsPane

您是否检查了小部件是否已丢弃?

编辑:没看到你在那里回答;)

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM