[英]details in one Row without any redundancy in the CATID
$query1 = "select *
from linkat_link
where emailuser = '$email2'
or linkname ='$domain_name2'
ORDER BY date desc
LIMIT $From,$PageNO";
id catid描述价格
------------------------------------
1 1个域名100
2 1本书50
3 2托管20
4 2 myservice 20
在此脚本中,我有一个问题,如果我有每个分类的ID,则我有一些重复的CATID,其内容不同但共享相同的CATID,我需要制作任何重复的CATID才能在其中显示,所有说明将是在同一行的同一行(单元格)中。 因此,每个CatID都将所有详细信息放在一行中,而CATID中没有任何冗余
使用:
SELECT t.catid,
GROUP_CONCAT(t.description),
GROUP_CONCAT(t.price)
FROM LINKAT_LINK t
WHERE t.emailuser = mysql_real_escape_string($email2)
OR t.linkname = mysql_real_escape_string($domain_name2)
GROUP BY t.catid
ORDER BY t.date DESC
LIMIT mysql_real_escape_string($From), mysql_real_escape_string($PageNO)
...将返回:
catid description price
--------------------------------
1 domain name,book 100,50
2 hosting,myservice 20,20
采用:
<?php
$query1 = "SELECT t.catid,
GROUP_CONCAT(t.description) AS grp_desc,
GROUP_CONCAT(t.price) AS grp_price
FROM LINKAT_LINK t
WHERE t.emailuser = mysql_real_escape_string($email2)
OR t.linkname = mysql_real_escape_string($domain_name2)
GROUP BY t.catid
ORDER BY t.date DESC
LIMIT mysql_real_escape_string($From), mysql_real_escape_string($PageNO)";
$result = mysql_query($query1);
while($row = mysql_fetch_array($result)) {
echo "CatID:{$row['catid']} <br>" .
"Description : {$row['grp_desc']} <br>" .
"Price : {$row['grp_price']} <br><br>";
} ?>
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