[英]Convert a Julian Date to Regular Calendar Date
如何将7位朱利安日期转换为MM / dd / yyy等格式?
找到了一个有用的网站: http : //www.rgagnon.com/javadetails/java-0506.html
这应该做的伎俩:
public static int[] fromJulian(double injulian) {
int jalpha,ja,jb,jc,jd,je,year,month,day;
double julian = julian + HALFSECOND / 86400.0;
ja = (int) julian;
if (ja>= JGREG) {
jalpha = (int) (((ja - 1867216) - 0.25) / 36524.25);
ja = ja + 1 + jalpha - jalpha / 4;
}
jb = ja + 1524;
jc = (int) (6680.0 + ((jb - 2439870) - 122.1) / 365.25);
jd = 365 * jc + jc / 4;
je = (int) ((jb - jd) / 30.6001);
day = jb - jd - (int) (30.6001 * je);
month = je - 1;
if (month > 12) month = month - 12;
year = jc - 4715;
if (month > 2) year--;
if (year <= 0) year--;
return new int[] {year, month, day};
}
简单的方法就在这里,这将返回大约100%准确的信息。
String getDobInfo(double doubleString){
SweDate sweDate = new SweDate(doubleString);
int year = sweDate.getYear();
int month = sweDate.getMonth();
int day = sweDate.getDay();
// getting hour,minute and sec from julian date
int hour = (int) Math.floor(sweDate.getHour());
int min = (int) Math
.round((sweDate.getHour() - Math.floor(hour)) * 60.0);
int sec = (int) (((sweDate.getHour() - Math.floor(hour)) * 60.0 - Math
.floor(min)) * 60.0);
return "DOB:(DD:MM:YY) "+day+":"+month+":"+year+" TOB:(HH:MM:SS) "+hour+":"+min+":"+sec;
}
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从Java 8开始,这将成为获取LocalDate
的单行程序:
LocalDate.MIN.with(JulianFields.JULIAN_DAY, julianDay)
.format(DateTimeFormatter.ofPattern("MM/dd/yyyy"));
julianDay
是你的7位数字。
你真的是指天文学家使用的儒略日期吗? 序数日期(指定为年份(四位数)和该年份内的日期(3位数))有时会被错误地称为朱利安日期。
static String formatOrdinal(int year, int day) {
Calendar cal = Calendar.getInstance();
cal.clear();
cal.set(Calendar.YEAR, year);
cal.set(Calendar.DAY_OF_YEAR, day);
Date date = cal.getTime();
SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yyyy");
return formatter.format(date);
}
这将在当地时间00:00给你一个日期; 您可能希望将日历上的时区设置为GMT,具体取决于应用程序。
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