php json_encode返回null

Question

Array
(
    [sEcho] => 1
    [iTotalRecords] => 7521
    [iTotalDisplayRecords] => 1
    [aaData] => Array
        (
            [0] => Array
                (
                    [0] => Nordic Capital Buys SiC Processing
                    [1] => 2010-06-21/nordic-capital-buys-sic-processing
                    [2] => PEHub Media
                    [3] => Business
                    [4] => completed
                    [5] => Nordic Capital has acquired a 70% stake in SiC Processing AG, a German industrial recycling company, from Frog Capital. No sale price was disclosed.  SiC Processing’s founding family retains a 25% holding, while former lead investor Zouk Ventures retains a 5% stake.

                    [6] => Admin, China, Frog Capital, Germany, Italy, Iyad Omari, Manufacturing, Norway, PEHub Media, Photovoltaic Wafer Manufacturing, Renewable Energy, Semiconductor, United States
                )

        )

)

echo json_encode($myArr);

{“sEcho”：“1”，“iTotalRecords”：7521，“iTotalDisplayRecords”：“1”，“aaData”：[[“”Nordic Capital购买SiC处理</a> </ div>“，”2010-06- 21 / nordic-capital-buys-sic-processing </ div>“，”PEHub Media“，”Business“，”completed“， null ，”Admin，China，Frog Capital，德国，意大利，Iyad Omari，制造业，挪威，PEHub Media，光伏晶圆制造，可再生能源，半导体，美国]]}

注意完成后字符串中间的null

为什么这样，我需要执行什么转义/操作才能对其进行编码？

我试过， addslashes

Answer 1

从手册：

请注意，如果您尝试对包含非utf值的数组进行编码，则会在生成的JSON字符串中获取空值。 您可以使用array_map函数批量编码数组的所有元素：

$encodedArray = array_map(utf8_encode, $myArr);
echo json_encode($encodedArray);

Answer 2

我只是尝试了完全相同的代码，它返回以下内容：

{"var1":"test string","var2":"Nordic Capital has acquired a 70% stake in SiC Processing AG, a German industrial recycling company, from Frog Capital. No sale price was disclosed.  SiC Processing\u2019s founding family retains a 25% holding, while former lead investor Zouk Ventures retains a 5% stake.","var3":"test string 3"}

您运行的是哪个版本的PHP？ 这是来自您的本地主机还是您在远程盒子上运行它？

Answer 3

实际上它不会返回null， http：//codepad.org/A34KdUf5 。

也许您的PHP版本不支持json_encode（）。

Answer 4

在5.2.13上为我工作。 确保您至少使用PHP 5.2.0并且PHP未使用--disable-json编译。 您可能还想检查是否启用了错误报告（和/或日志记录）。

Answer 5

更简单的方法是$store_name = utf8_encode(name_of_varaible)但请确保您的字符集是ISO-8859-1.