[英]Problem Deserializing with Jackson using JAXB annotations in Spring MVC
在调用服务时,我无法让杰克逊正确地将json反序列化为一个对象(特别是我们使用Jackson的能力来使用JAXB注释,因为我们也希望服务使用XML)。 我正在使用Spring MVC,我正在使用RestTemplate类来调用服务。
这是我为junit设置MappingJacksonHttpMessageConverter的地方:
ObjectMapper jsonMapper = new ObjectMapper();
AnnotationIntrospector introspector = new JaxbAnnotationIntrospector();
jsonMapper.getDeserializationConfig().setAnnotationIntrospector(introspector);
jsonMapper.getSerializationConfig().setAnnotationIntrospector(introspector);
jsonMapper.getSerializationConfig().setSerializationInclusion(Inclusion.NON_NULL);
MappingJacksonHttpMessageConverter jacksonConverter = new MappingJacksonHttpMessageConverter();
jacksonConverter.setObjectMapper(jsonMapper);
List<HttpMessageConverter<?>> converters = new ArrayList<HttpMessageConverter<?>>();
converters.add(jacksonConverter);
template.setMessageConverters(converters);
我这样称呼服务:
HttpHeaders requestHeaders = new HttpHeaders();
requestHeaders.set("Accept", "application/json");
HttpEntity<String> requestEntity = new HttpEntity<String>(requestHeaders);
ResponseEntity<NamedSystem> responseEntity = template.exchange(baseURL + "/{NamedSystemId}",
HttpMethod.GET, requestEntity, NamedSystem.class, orgId1);
我的NamedSystem
类设置如下:
@XmlRootElement(name = "NamedSystem", namespace = "http://schemas.abc.workplace.com/NamedSystem")
public class NamedSystem {
private String id;
private String name;
private String description;
private Set<NamedSystemAlias> aliases;
private String href;
@XmlAttribute(required = false, name = "id")
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
@XmlAttribute(required = false, name = "name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@XmlAttribute(required = false, name = "description")
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
@XmlElementWrapper(required = false, name = "aliases", namespace = "http://schemas.abc.workplace.com/NamedSystem")
@XmlElement(required = false, name = "alias", namespace = "http://schemas.abc.workplace.com/NamedSystem")
public Set<NamedSystemAlias> getAliases() {
return aliases;
}
public void setAliases(Set<NamedSystemAlias> aliases) {
this.aliases = aliases;
}
@XmlAttribute(required = true, name = "href")
public String getHref() {
return href;
}
public void setHref(String href) {
this.href = href;
}
}
这是导致的错误:
org.springframework.web.client.ResourceAccessException: I/O error: Unrecognized field "NamedSystem" (Class com.workplace.abc.named.NamedSystem), not marked as ignorable
at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@c1429c; line: 1, column: 2]; nested exception is org.codehaus.jackson.map.JsonMappingException: Unrecognized field "NamedSystem" (Class com.workplace.abc.named.NamedSystem), not marked as ignorable
at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@c1429c; line: 1, column: 2]
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:453)
....
Caused by: org.codehaus.jackson.map.JsonMappingException: Unrecognized field "NamedSystem" (Class com.workplace.abc.named.NamedSystem), not marked as ignorable
at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@c1429c; line: 1, column: 2]
at org.codehaus.jackson.map.JsonMappingException.from(JsonMappingException.java:159)
at org.codehaus.jackson.map.deser.StdDeserializationContext.unknownFieldException(StdDeserializationContext.java:247)
at org.codehaus.jackson.map.deser.StdDeserializer.reportUnknownProperty(StdDeserializer.java:366)
at org.codehaus.jackson.map.deser.StdDeserializer.handleUnknownProperty(StdDeserializer.java:352)
at org.codehaus.jackson.map.deser.BeanDeserializer.handleUnknownProperty(BeanDeserializer.java:543)
at org.codehaus.jackson.map.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:402)
at org.codehaus.jackson.map.deser.BeanDeserializer.deserialize(BeanDeserializer.java:287)
at org.codehaus.jackson.map.ObjectMapper._readMapAndClose(ObjectMapper.java:1588)
at org.codehaus.jackson.map.ObjectMapper.readValue(ObjectMapper.java:1172)
at org.springframework.http.converter.json.MappingJacksonHttpMessageConverter.readInternal(MappingJacksonHttpMessageConverter.java:132)
at org.springframework.http.converter.AbstractHttpMessageConverter.read(AbstractHttpMessageConverter.java:154)
at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:74)
at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:619)
at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:1)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:446)
... 32 more
它似乎无法识别rootElement'NamedSystem'能够反序列化。 我怎么能这样做呢? 我已经看到使用相同的JAXB注释的示例,它们工作正常,所以我不确定我的情况有什么不同,或者我怎么强迫它正确地反序列化它。 如果有人可以提供任何帮助,我会很感激。
如果有人遇到这种问题,这可能会为你解决: 启用Jackson在序列化时不输出类名(使用Spring MVC)
请参阅我的回答并按照链接获取示例。
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