是否可以合并“两个具有聚合和分组依据的查询”（结果集）？

Question

1

Select id,count(*) as totalX FROM my_table WHERE x_factor = 1 GROUP BY id

结果集 ：

 id        totalX
 --------- --------------
         9             34
        10              6
        11             21
        12              3  

2

Select id,count(*) as totalY FROM my_table WHERE y_factor = 1 GROUP BY id

结果集2：

 id        totalY
 --------- --------------
         9             334
        10              56
        11             251
        12              93 

有没有办法我可以做到这一点：

 id        totalX        totalY         
 --------- --------------  --------------  
         9             34              334 
        10              6               56 
        11             21              251 
        12              3               93 

我想在RHEL 5上使用Sybase 12.5的解决方案，我也想知道在其他任何数据库系统中是否可行。

---谢谢您的回答-

Comparing EXECUTION TIME: (For a certain query) 
 Query 1:
Execution Time 61.
SQL Server cpu time: 6100 ms.  SQL Server elapsed time: 12133 ms.

Query 2:
Execution Time 53.
SQL Server cpu time: 5300 ms.  SQL Server elapsed time: 12090 ms.

Query X(1+2):
Execution Time 84.
SQL Server cpu time: 8400 ms.  SQL Server elapsed time: 21456 ms.

Answer 1

通过对列使用CASE / WHEN并基于true / false求和1或0，您可以在同一查询中获得两者。此外，如果希望将另一个值的总和作为另一个，则可以执行相同的操作列...只需将其替换为真实值即可，而不是1。

select 
      id,
      sum( CASE WHEN x_factor = 1 THEN 1 ELSE 0 END ) as X_Count, 
      sum( CASE WHEN y_factor = 1 THEN 1 ELSE 0 END ) as Y_Count
  from
      yourTable
  group by
      id

Answer 2

这应该工作：

SELECT id, 
       sum(case when x_factor = 1 then 1 else 0 end) as totalX,
       sum(case when y_factor = 1 then 1 else 0 end) as totalY
    FROM my_table 
    WHERE x_factor = 1 
        OR y_factor = 1
    GROUP BY id

Answer 3

CASE ... {0 | 1}对于人们来说是个不错的窍门，但我认为问题可能比这更简单。 你有没有尝试过：

SELECT id, COUNT(x_factor) AS count_x, COUNT(y_factor) AS count_y FROM my_table GROUP BY id