后缀的C ++中缀

Question

编译时出现以下错误：

convert.cpp: In function 'std::string convert()':
convert.cpp:62: error: expected primary-expression before 'else'
convert.cpp:62: error: expected `;' before 'else'
convert.cpp:108: error: expected `}' at end of input
convert.cpp:108: error: expected `}' at end of input 
convert.cpp:108: error: expected `}' at end of input 
convert.cpp:108: error: expected `}' at end of input 
convert.cpp:108: error: expected `}' at end of input

码：

#include<iostream>
#include<stack>
#include<string>
using namespace std;

string infix;  // infix expression string
string operand;
string operate;
stack <string> mystack; // this stack is used to push the operator
string postfix;  // postfix string where the operand is appended

//....................................................................
// this function read the infix expression from user 
string input()
{
 cout<<" Enter the damn infix expression: "<<endl; 
 getline(cin, infix);
 return infix;
}
//......................................................................
// this function checks for operator precedence in the stack
int precedence(string e)
{
int f;
if(e == "*" || e== "/" || e =="%")
 f = 2;
else
{
if(e == "+" || e == "-")
 f = 1;
}

if(e=="."){
f=0;
}

return f;

}




//....................................................................
// This function converts infix to postfix
string convert()
{ 
 for(int i=0; i<infix.length(); i++)
 { 

  switch(infix[i]){

  // operate case start  
  case '+': case'-': case'*': case'/': case'^': case '(': case ')': case'.':

  operate=infix[i];
  {
  if(mystack.empty() || precedence(operate)>= precedence(mystack.top()))
  {
    mystack.push(operate);           

   else
   {
    while(precedence(operate)<= precedence(mystack.top()))
    {
     postfix.append(mystack.top());
     mystack.pop();
    }

    mystack.push(operate); 
   }

  }
  }//operate case closed

  default:        //when operand string char is parsed
  {
                        operand=infix[i];
                        postfix.append(operand);
                        break;

  } // default case closed

  }//switch closed

 }

while(!mystack.empty())
{
 postfix.append(mystack.top())
 mystack.pop();
}

return postfix;
cout<<postfix;
}



//...................................................................
int main()
{

input();

convert();
cout<<"postfix is "<<postfix<<endl;
} 

Answer 1

看来您的代码只是缺少一些右花括号。 就这样。

例如，看这个：

  operate=infix[i];
  {
  if(mystack.empty() || precedence(operate)>= precedence(mystack.top()))
  {
    mystack.push(operate);           

   else
   {
    while(precedence(operate)<= precedence(mystack.top()))

else语句前的结束}在哪里。 只需检查您的代码并修复这些愚蠢的错误即可。

这将是一个更容易摆脱这些事情你自己，如果你做了空格和缩进一点点整洁。

Answer 2

“在其他情况之前预期的主要表达”诊断是编译器作者向您粗鲁地向您报告“其他”而没有前面的“ if”或“ else if”的方式。 Alexander Rafferty正确地指出这是因为代码具有...

if (condition) {
  // ...
  else { }

...当你的意思是...

if (condition) {
   // ...
}
else {
}

……尽管也许您是偶然删除了一大堆东西，并且很幸运地删除了这些代码，导致代码无法解析，所以您将意识到有些错误。

Answer 3

看一下这些行：

if(mystack.empty() || precedence(operate)>= precedence(mystack.top()))
{
   mystack.push(operate);           

else