SQL：如何将其转换为一个查询？

Question

UPDATE a
    SET CountOfAA=dt.CountOf
    FROM @MediaResurce  a
        INNER JOIN (SELECT 
                        aa.Sku,ISNULL(COUNT(bb.sku),0) AS CountOf
                        FROM @MediaResurce                      aa
                            LEFT OUTER JOIN @MediaResurce_Pics  bb 
                            ON aa.sku=bb.sku
                        WHERE somecol = 0
                        GROUP BY aa.Sku
                   ) dt ON a.sku=dt.sku

/////////////

UPDATE a
    SET CountOfBB=dt.CountOf
    FROM @MediaResurce  a
        INNER JOIN (SELECT 
                        aa.Sku,ISNULL(COUNT(bb.sku),0) AS CountOf
                        FROM @MediaResurce                      aa
                            LEFT OUTER JOIN @MediaResurce_Pics  bb 
                            ON aa.sku=bb.sku
                         WHERE somecol = 1
                        GROUP BY aa.Sku
                   ) dt ON a.sku=dt.sku

Answer 1

这应该是您要寻找的：

UPDATE a
SET 
  CountOfAA = dt.CountOfAA,
  CountOfBB = dt.CountOfBB
FROM @MediaResurce  a
INNER JOIN (
  SELECT
    SUM(
      case somecol 
        when 0 then 1
        else 0
      end
    ) AS CountOfAA,
    SUM(
      case somecol 
        when 1 then 1
        else 0
      end
    ) AS CountOfBB
    FROM @MediaResurce aa
    LEFT OUTER JOIN @MediaResurce_Pics bb 
      ON aa.sku=bb.sku
) dt ON a.sku=dt.sku

您可以根据您的“ somecol”的要求将SUM“ 1”或“ 0”求和，而不用对两个单独的查询进行计数。

Answer 2

好吧，你可以轻松地做到这一点

UPDATE a
SET CountOfAA=dt.CountOf,
    CountOfBB=dt2.CountOf
FROM @MediaResurce  a
    INNER JOIN (SELECT 
                    aa.Sku,ISNULL(COUNT(bb.sku),0) AS CountOf
                    FROM @MediaResurce                      aa
                        LEFT OUTER JOIN @MediaResurce_Pics  bb 
                        ON aa.sku=bb.sku
                    WHERE somecol = 0
                    GROUP BY aa.Sku
               ) dt ON a.sku=dt.sku
    INNER JOIN (SELECT 
                    aa.Sku,ISNULL(COUNT(bb.sku),0) AS CountOf
                    FROM @MediaResurce                      aa
                        LEFT OUTER JOIN @MediaResurce_Pics  bb 
                        ON aa.sku=bb.sku
                     WHERE somecol = 1
                    GROUP BY aa.Sku
               ) dt2 ON a.sku=dt2.sku

这是一种懒惰且无效的方法，另一种方法可能是这样的：

SUM(somecol) AS 'count where somecol=1'
count(*) - SUM(somecol) AS 'count where somecol=0'
...
where somecol in (0,1) //only need if somecol can be something other than 0 or 1!