[英]SQL : Using GROUP BY and MAX on multiple columns
我有一个 SQL 查询问题。 让我们以这个示例数据为例
itemID catID attrib1 attrib2
1 1 10 5
2 1 10 7
3 1 5 10
4 2 18 15
我想为每个类别返回最好的项目(attrib1 优先于 attrib2)
显然, SELECT catID, MAX(attrib1), MAX(attrib2) FROM test_table GROUP BY catID
不起作用,因为它会为第一只猫返回 10 & 10。
那么无论如何要告诉 MySQL 从 attrib2 行中选择最大值,但只考虑 attrib1 也是最大值的那些? 即返回以下数据
catID attrib1 attrib2
1 10 7
2 18 15
您可以获得最好的 attrib1 值,然后加入 attrib2 值并为每个 attrib1 值获取最好的值:
select t2.catID, t2.attrib1, max(t2.attrib2)
from
(
select catID, max(attrib1) as attrib1
from test_table
group by catID
) t1
inner join test_table t2 on t2.catID = t1.catID and t2.attrib1 = t1.attrib1
group by t2.catID, t2.attrib1
使用:
SELECT x.catid,
x.max_attrib1 AS attrib1,
(SELECT MAX(attrib2)
FROM YOUR_TABLE y
WHERE y.catid = x.catid
AND y.attrib1 = x.max_attrib1) AS attrib2
FROM (SELECT t.catid,
MAX(t.attrib1) AS max_attrib1
FROM YOUR_TABLE t
GROUP BY t.catid) x
SELECT tt.catId, tt.attrib1, MAX(tt.attrib2)
FROM test_table tt
GROUP BY tt.catID, tt.attrib1
WHERE tt.attrib1 = (SELECT MAX(t2.attrib1) FROM test_table t2 WHERE t2.catID = tt.catID)
SELECT catID, max1, max2 FROM
((SELECT Max(attrib1) as max1, catID GROUP BY attrib1) as t1
INNER JOIN
(SELECT MAX(attrib2) as max2, catID GROUP BY attrib2) as t2
ON t1.catID = t2.catID) as t3
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