我应该如何在Oracle中加入这3个SQL查询？

Question

我有以下3个查询：

SELECT
  title, year, MovieGenres(m.mid) genres,
  MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers,
  synopsis, poster_url
FROM movies m
WHERE m.mid = 1;

SELECT AVG(rating) FROM movie_ratings WHERE mid = 1;

SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1;

我需要将它们加入一个查询中。 我能够这样做：

SELECT
  title, year, MovieGenres(m.mid) genres,
  MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers,
  synopsis, poster_url, AVG(rating) average, COUNT(rating) count
FROM movies m INNER JOIN movie_ratings mr
  ON m.mid = mr.mid
WHERE m.mid = 1
GROUP BY
  title, year, MovieGenres(m.mid), MovieDirectors(m.mid),
  MovieWriters(m.mid), synopsis, poster_url;

但是我真的不喜欢那种“巨大的” GROUP BY，有没有更简单的方法呢？

Answer 1

您可以执行以下操作：

SELECT title
      ,year
      ,MovieGenres(m.mid) genres
      ,MovieDirectors(m.mid) directors
      ,MovieWriters(m.mid) writers
      ,synopsis
      ,poster_url
      ,(select avg(mr.rating) 
         from movie_ratings mr 
        where mr.mid = m.mid) as avg_rating
      ,(select count(rating)  
         from movie_ratings mr 
        where mr.mid = m.mid) as num_ratings
  FROM movies m
 WHERE m.mid = 1;

甚至

with grouped as(
   select avg(rating)   as avg_rating 
         ,count(rating) as num_ratings
     from movie_ratings 
    where mid = 1
)
select title
      ,year
      ,MovieGenres(m.mid) genres
      ,MovieDirectors(m.mid) directors
      ,MovieWriters(m.mid) writers
      ,synopsis
      ,poster_url
      ,avg_rating
      ,num_ratings
  from movies m cross join grouped
 where m.mid = 1;

Answer 2

我想我看不到具有多个GroupBy列的问题。 这是SQL中非常常见的模式。 当然，代码的清晰性通常在情人眼中。

检查两种方法的解释计划； 我的猜测是，使用原始版本将获得更好的性能，因为它只需要处理一次movie_ratings表。 但是我还没有检查过，那将取决于数据和安装。

Answer 3

怎么样

SELECT
  title, year, MovieGenres(m.mid) genres,
  MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers,
  synopsis, poster_url,
  (SELECT AVG(rating) FROM movie_ratings WHERE mid = 1) av,
  (SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1) cnt 
FROM movies m
WHERE m.mid = 1;

要么

SELECT
  title, year, MovieGenres(m.mid) genres,
  MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers,
  synopsis, poster_url,
  av.av,
  cnt.cnt 
FROM movies m,
  (SELECT AVG(rating) av FROM movie_ratings WHERE mid = 1) av,
  (SELECT COUNT(rating) cnt FROM movie_ratings WHERE mid = 1) cnt 
WHERE m.mid = 1;