如何在SQL Server中提取子字符串

Question

我有一个类似okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos

我想从数据中提取name = value 。

如何使用SQL Server 2008高效地做到这一点？ 谢谢

Answer 1

尝试这个

;
With MyTable as
(
    SELECT 'okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos' FullString
    UNION 
    SELECT 'fkgbokfgbo&name=fokdofkd&okfaos' FullString
    UNION 
    SELECT 'okbogkbogkbokgbok' FullString
),
PatternIndex as
(
    Select 
        FullString + '&' FullString, 
        CharIndex ('&name=', FullString) + 1 LocationOfEqualSign, 
        CharIndex ('&', FullString, CharIndex ('&name=', FullString)+1) as NextBreak
    from MyTable
),
SplitNameValue AS
(
    Select 
        FullString, 
        CASE 
            WHEN NextBreak <> 0 THEN 
            SubString (FullString, LocationOfEqualSign, NextBreak-LocationOfEqualSign) 
            ELSE '' END
        as NameValuePair
    From PatternIndex
)
SELECT * 
FROM SplitNameValue

退货

FullString                                                NameValuePair
--------------------------------------------------------- ---------------------------------------------------------
fkgbokfgbo&name=fokdofkd&okfaos                           name=fokdofkd
okbogkbogkbokgbok                                         
okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos name=fokdofkd

(3 row(s) affected)

Answer 2

我认为这将起作用：

Declare @String varchar(100)

Set @String = 'okbogkbogkbokgbokgobkgobkofkgbokfgbo&name=fokdofkd&okfaos'

Select SubString(@String,CharIndex('name=',@String),len(@String)) 

这将产生：

'名称= fokdofkd＆okfaos'

Answer 3

SELECT 'name=' + SUBSTRING(field, CHARINDEX('name=', field), CHARINDEX('&', SUBSTRING(field, CHARINDEX('name=' ,field))))

Answer 4

类似于...

select substring(ColumnName, charindex('name=',ColumnName,1),len(ColumnName))