[英]Nested SQL query using CASE statements
如何通过执行以下两个查询(步骤),仅编写一个SQL查询来获得相同的结果:
第一步:
SELECT old_id, new_id FROM history WHERE flag = 1;
结果:
+--------+--------+
| old_id | new_id |
+--------+--------+
| 11 | 22 |
| 33 | 44 |
| 55 | 66 |
+--------+--------+
然后,使用以前的结果,执行以下查询:
UPDATE other_tabla SET somefk_id = CASE somefk_id
WHEN 11 THEN 22
WHEN 33 THEN 44
WHEN 55 THEN 66
END WHERE somefk_id IN (11,33,55)
我认为这就是您所描述的:
UPDATE `other_tablea`
JOIN `history` ON history.old_id = other_tablea.somefk_id AND history.flag = 1
SET other_tablea.somefk_id = history.new_id
子查询似乎可以解决问题:
update other_tabla
set somefk_id = coalesce((
select new_id
from history
where flag = 1
and old_id = other_tabla.somefk_id
), other_tabla.somefk_id)
你不需要case
update
other_table, history
set
other_table.somefk_id=history.new_id
where
other_table.somefk_id=history.old_id and history.flag=1;
您可以使用临时表存储第一个查询的结果,然后在第二个查询中重新使用数据。
SELECT old_id, new_id
INTO #tmpTable1
FROM history
WHERE flag = 1;
UPDATE other_tabla SET somefk_id = t.new.id
FROM other_tabla as o
INNER JOIN #tmpTable1 t ON o.somefk_id=t.old_id
DROP TABLE #tmpTable1
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