[英]Java - array list to output all factors
我被要求创建一个方法,将所有因子作为数组列表返回。 任何帮助都会受到赞赏,因为我已经被困了一段时间了。
/**
* Determines whether the number has factors.
*
* @return true iff the number has a factor
*/
public boolean hasMoreFactors()
{
if (number >= 2) {
return true;
} else {
return false;
}
// return (number >= 2);
}
/**
* Is number divisible by a given other number?
*
* @param otherNumber the number we test whether it divides the object's number
* @return true iff the number is divisible by otherNumber
*/
public boolean isDivisible(int otherNumber)
{
if (number % otherNumber == 0) {
return true;
} else {
return false;
}
}
/**
* Determine next factor.
* pre-condition: call only if hasMoreFactors
* returns true
*
* @return a factor of the object's number
*/
public int nextFactor()
{
int triedFactor = 2;
while (! isDivisible(triedFactor)) {
triedFactor = triedFactor+1;
}
number = number / triedFactor;
return triedFactor;
}
/**
* Print all factors of the generator's number on standard output.
*/
public void printAllFactors()
{
System.out.println("Factors of " + number);
while (hasMoreFactors()) {
System.out.println(nextFactor());
}
System.out.println("That's it.");
}
/**
* Main method: Read an integer and print all its factors.
*/
public static void main(String[] args)
{
System.out.print("Please enter a number greater or equal 2: ");
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
System.out.println();
FactorGenerator gen = new FactorGenerator(num);
gen.printAllFactors();
}
}
而不是在这一行打印出来:
System.out.println(nextFactor());
创建一个ArrayList:
List<Integer> list = new ArrayList<Integer>();
并将它们存储在其中:
list.add(nextFactor());
看起来你错过了一个数字具有相同因子多次的情况。 例如,4 = 2 * 2,但是在尝试了2之后,您增加并尝试了下一个3。 您需要继续尝试每个候选人,直到不再成为一个因素为止。
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