Join On中的Hibernate MySQL查询错误未知列

Question

尝试在MySQL中使用Hibernate时遇到一个奇怪的错误。 我有以下命名查询：

SELECT SUM(s.plotline.value), s.character FROM Story as s WHERE s.chapter.chapterID = ?1 GROUP BY s.character ORDER BY SUM(s.plotline.value)

它将转换为以下SQL语句：

    select sum(plotline1_.Value) as col_0_0_, story0_.CharacterID as col_1_0_, character2_.CharacterID as Characte1_5_,
 character2_.AuthorID as AuthorID5_, character2_.BookID as BookID5_, character2_.CharacterName as Characte2_5_,
 character2_.LastModified as LastModi3_5_
 from fantasy.story story0_, fantasy.plotline plotline1_ 
inner join fantasy.character character2_ on story0_.CharacterID=character2_.CharacterID 
where story0_.PlotlineID=plotline1_.PlotlineID and story0_.ChapterID= 4
group by story0_.CharacterID 
order by count(plotline1_.Value)

当我执行此操作时，我得到：

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'story0_.CharacterID' in 'on clause'
    sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
    sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
    java.lang.reflect.Constructor.newInstance(Unknown Source)
    com.mysql.jdbc.Util.handleNewInstance(Util.java:407)
    com.mysql.jdbc.Util.getInstance(Util.java:382)

如果将查询更改为此并直接在SQL中运行，它将正常运行：

select sum(plotline1_.Value) as col_0_0_, story0.CharacterID as col_1_0_, character2_.CharacterID as Characte1_5_,
 character2_.AuthorID as AuthorID5_, character2_.BookID as BookID5_, character2_.CharacterName as Characte2_5_,
 character2_.LastModified as LastModi3_5_
 from fantasy.story story0, fantasy.plotline plotline1_ 
inner join fantasy.character character2_ on CharacterID = character2_.CharacterID 
where story0.PlotlineID=plotline1_.PlotlineID and story0.ChapterID= 4
group by story0.CharacterID 
order by count(plotline1_.Value)

这个问题有两个部分

1. 为什么要删除联接中对CharacterID的显式限定才能使此项工作？ 我的经验主要是使用SQL Server，如果尝试以这种方式编写查询，它实际上会失败。
2. 有没有办法让Hibernate以适当的形式给我查询或调整我的MySQL配置，以便它接受Hibernate生成查询的方式？

Answer 1

您的第一个请求不起作用，因为“ on子句”中的“ story0_”未知

from fantasy.story story0_, fantasy.plotline plotline1_ inner join fantasy.character character2_ on story0_.CharacterID=character2_.CharacterID 

当您编写“从A，B内部联接C”时，SQL（5.0及更高版本）仅考虑B和C之间的内部联接，然后仅在这两个表之间允许“ on子句”。

2解决方案应该起作用：

• 添加括号

from ( fantasy.story story0_, fantasy.plotline plotline1_ ) inner join fantasy.character character2_ on story0_.CharacterID=character2_.CharacterID

• 变更表格顺序

from fantasy.plotline plotline1_, fantasy.story story0_ inner join fantasy.character character2_ on story0_.CharacterID=character2_.CharacterID

有关更多详细信息，请访问： https : //bugs.mysql.com/bug.php?id=13551

我想您找到的解决方案是有效的，因为CharacterID也是plotline1_中的一个字段

我目前在使用Hibernate时遇到此问题，即使我发现了为什么SQL语句引发异常（以及如何更正它），我也不知道如何配置Hibernate来强制它生成这2种解决方案之一。

如果有人知道如何使用Hibernate进行操作，谢谢您的帮助！