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[英]Google maps v3 not a LatLngBounds or LatLngBoundsLiteral: not an Object name: "InvalidValueError"
[英]Google Maps v3 - Why is LatLngBounds.contains returning false
我有以下代码,我希望contains方法返回true,但它返回false:
var bounds = new google.maps.LatLngBounds(
new google.maps.LatLng(55.38942944437183, -2.7379201682812226),
new google.maps.LatLng(54.69726685890506, -1.2456105979687226)
);
var center = bounds.getCenter(); // (55.04334815163844, -1.9917653831249726)
var x = bounds.contains(center); // returns false
在同一页面上,map是对Map对象的引用,以下代码按预期返回true:
map.getBounds().contains(map.getBounds().getCenter())
为什么我对bounds.contains
调用会返回false?
啊,太棒了。 google.maps.LatLngBounds
构造函数需要SouthWest和NorthEast LatLng
参数。 我不知何故搞砸了我的坐标,而是通过了NorthWest和SouthEast!
var bounds = new google.maps.LatLngBounds(
new google.maps.LatLng(54.69726685890506,-2.7379201682812226),
new google.maps.LatLng(55.38942944437183, -1.2456105979687226)
);
var center = bounds.getCenter(); // still returns (55.04334815163844, -1.9917653831249726)
var x = bounds.contains(center); // now returns true
获得的经验: getCenter
并不关心您是否使用NorthWest和SouthEast创建了LatLngBounds
,但是如果您想要contains
返回有用的答案,则最好传入建议的SouthWest和NorthEast!
我想这更容易尝试。 它对我有用而不必担心NE或SW
var bounds = new google.maps.LatLngBounds();
bounds.extend(54.69726685890506,-2.7379201682812226);
bounds.extend(55.38942944437183, -1.2456105979687226);
var center = bounds.getCenter(); // still returns (55.04334815163844, -1.9917653831249726)
var x = bounds.contains(center); // now returns true
我知道这篇文章很老,但我来这里寻找答案,所以想到从我学到的东西中更新。
这是它对我有用的方式:
var bounds = new google.maps.LatLngBounds();
bounds.extend(54.69726685890506,-2.7379201682812226);
bounds.extend(55.38942944437183, -1.2456105979687226);
map.fitBounds(bounds);
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