获取客户端机器的IP地址

Question

我们在实验室中有10台计算机，我们设置了所有连接到LAN的计算机，以便我们可以共享文件，我的计算机充当主计算机，我只想获取连接到主计算机（即我的计算机）的所有IP地址）并列出它们，我的代码是

    System.Diagnostics.Process p = new System.Diagnostics.Process();
    p.StartInfo.FileName = "cmd ";
    p.StartInfo.UseShellExecute = false;
    p.StartInfo.Arguments = "/C net view";
    p.StartInfo.RedirectStandardOutput = true;
    p.Start();
    String output = p.StandardOutput.ReadToEnd();
    char[] delimiters = new char[] { '\n', '\\' };
    string[] s = output.Split(delimiters, StringSplitOptions.RemoveEmptyEntries);
    string hostName = Dns.GetHostName();
    IPHostEntry IPHost = Dns.GetHostEntry(hostName);
    Console.WriteLine(IPHost.HostName); // Output name of web host
    IPAddress[] address = IPHost.AddressList; // get list of IP address
    // Console.WriteLine("List IP {0} :", IPHost.HostName);
    if (address.Length > 0)
    {
        for (int i = 0; i < address.Length; i++)
        {
            Console.WriteLine(address[i]);
        }
    }


    p.WaitForExit();
    int z = s.Length - 5;

    string[] str1 = new string[z];
   // int i = 0;
    char[] saperator = { ' ' };
    for (int j = 3; j < s.Length - 2; j++)
    {
        //Console.WriteLine(s[i]);
       // str1[i] = (s[j].ToString()).Split(saperator)[0];
       // Console.WriteLine("IP Address {0}: {1} ", i, addr[i].ToString());
    }
    //Console.WriteLine(output);

    s = output.Split(new string[] { "\n,\\" }, StringSplitOptions.None);

    //Console.WriteLine(s[i]);
    //Console.WriteLine(output);
   // Console.WriteLine("IP Address : {1} ", i, AddressList[i].ToString());
    Console.ReadLine();

但是我得到了我机器的IP地址，我想在实验室里输入10个机器的IP地址。

Answer 1

而不是传递主机名，而是传递net view的结果。

foreach (string hostName in hostNames)
{
    //string hostName = Dns.GetHostName();
    IPHostEntry entry = Dns.GetHostEntry(hostName);
    Console.WriteLine(entry.HostName); // output name of web host
    IPAddress[] addresses = entry.AddressList; // get list of IP addresses
    foreach (var address in addresses)
    {
        Console.WriteLine(address);
    }
}