PHP联系表格未提交
[英]PHP Contact Form not submitting
问题描述
嗨，我以前使用这个非常简单的PHP联系脚本成功，但是当我尝试在新的HTML页面上实现它时，表单将无法提交。 谁能看到任何明显的错误？ 任何帮助将非常感激
这是表单的html：
<div id="formContainer">
<form action="form.php" method="post" id="contactForm">
<fieldset>
<legend>Your details</legend>
<label for="name">Name *</label>
<input type="text" id="name">
<label for="email">Email *</label>
<input type="email" id="email">
<label for="tel">Telephone</label>
<input type="tel" id="tel">
</fieldset>
<fieldset>
<legend>Tutoring</legend>
<label for="type">Type of lesson</label>
<select name="type" id="type">
<option>Individual</option>
<option>Group</option>
</select>
<label for="subject">Subject</label>
<input name="subject" list="subjects" id="subject">
<datalist id="subjects">
<option>English</option>
<option>Biology</option>
<option>Geography</option>
</datalist>
<label for="level">Your level</label>
<select name="level" id="level">
<option>Beginner</option>
<option>GCSE</option>
<option>A-Level</option>
<option>University</option>
</select>
<label for="hours">Hours/week</label>
<input type="number" id="hours">
<label for="info">Additional Information</label>
<textarea name="info" id="info" rows="10" cols="6"></textarea>
</fieldset>
<input type="submit" name="submit" value="Send" id="sendButton">
<input type="hidden" name="submit_check" value="1" />
</form>
</div>
这是简单的PHP脚本：
<?php
if ($_POST["email"]<>'') {
$ToEmail = 'onjegolders@gmail.com';
$EmailSubject = 'Site contact form ';
$mailheader = "From: ".$_POST["email"]."\r\n";
$mailheader .= "Reply-To: ".$_POST["email"]."\r\n";
$mailheader .= "Content-type: text/html; charset=iso-8859-1\r\n";
$MESSAGE_BODY = "Name: ".$_POST["name"]."<br>";
$MESSAGE_BODY .= "Email: ".$_POST["email"]."<br>";
$MESSAGE_BODY = "Telephone: ".$_POST["tel"]."<br>";
$MESSAGE_BODY = "Type: ".$_POST["type"]."<br>";
$MESSAGE_BODY = "Subject: ".$_POST["subject"]."<br>";
$MESSAGE_BODY = "Level: ".$_POST["level"]."<br>";
$MESSAGE_BODY = "Hours required: ".$_POST["hours"]."<br>";
$MESSAGE_BODY .= "Additional information: ".nl2br($_POST["info"])."<br>";
mail($ToEmail, $EmailSubject, $MESSAGE_BODY, $mailheader) or die ("Failure");
?>
<html>
<h3>Thanks for your email</h3>
<h4>I'll get back to you as soon as possible</h4>
<a href="index.html"><p>Click here to go back to previous page</p></a>
</html>
<?php
} else {
?>
<html>Sorry, this form didn't work</html>
<?php
};
?>
5 个解决方案
解决方案1
3 已采纳 2011-04-19 10:29:17
试试吧
if ( !empty($_POST["email"]) )
但是，您可以使用以下命令检查该页面中发布的内容：
echo '<pre>';
var_dump( $_POST );
解决方案2
1 2011-04-19 10:43:18
将form.php更改为以下内容
<?php
if ($_POST["email"]<>'') {
$ToEmail = 'onjegolders@gmail.com';
$EmailSubject = 'Site contact form ';
$mailheader = "From: ".$_POST["email"]."\r\n";
$mailheader .= "Reply-To: ".$_POST["email"]."\r\n";
$mailheader .= "Content-type: text/html; charset=iso-8859-1\r\n";
$MESSAGE_BODY = "Name: ".$_POST["name"]."<br>";
$MESSAGE_BODY .= "Email: ".$_POST["email"]."<br>";
$MESSAGE_BODY = "Telephone: ".$_POST["tel"]."<br>";
$MESSAGE_BODY = "Type: ".$_POST["type"]."<br>";
$MESSAGE_BODY = "Subject: ".$_POST["subject"]."<br>";
$MESSAGE_BODY = "Level: ".$_POST["level"]."<br>";
$MESSAGE_BODY = "Hours required: ".$_POST["hours"]."<br>";
$MESSAGE_BODY .= "Additional information: ".nl2br($_POST["info"])."<br>";
mail($ToEmail, $EmailSubject, $MESSAGE_BODY, $mailheader) or die ("Failure");
echo <<<EXCERPT
<html>
<h3>Thanks for your email</h3>
<h4>I'll get back to you as soon as possible</h4>
<a href="index.html"><p>Click here to go back to previous page</p></a>
</html>
EXCERPT;
} else {
echo "<html>Sorry, this form didn't work</html>";
}
?>
解决方案3
0 2011-04-19 10:35:51
在你的
if ($_POST["email"] <> '') {
改变成
if ($_POST["email"] != '') {
解决方案4
0 2011-04-19 10:40:32
你应该试试这个：
if(!empty($_POST["email"])){
//your email preparation code
}
使用这个：
if($_POST["email" <> ''){
//your email preparation code
}
的! 基本上不是 ，所以!empty意味着不是空的
解决方案5
0 2011-04-19 10:50:18
你也可以使用：
if ($_POST["email"]) {
这很像!= ""或empty()检查。 PHP被接受以很好地处理表单。 你可以让它探测传入的表单字段。 它对字符串使用了一些魔术布尔转换规则，大多数情况下它会完成你想要的。
这种更简单风格的另一个优点是，如果启用E_ALL和E_NOTICE（= debug）error_reporting模式，它可以简化调试。
PHP联系表单随机提交
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