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传递非专业模板作为模板参数

[英]Passing unspecialized template as a template parameter

我可以做点什么

template<class Key, class Data, class Compare = less<Key>, template<typename T> class Allocator<T> = allocator<T> >
    class mymap {
        typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap; 
        typedef vector<Data,Allocator<Data> > storageVector;
}

因此,模板将被非专业地传递给该类,并在以后实例化。

是的,这是一个最小的可编译示例:

#include <map>
#include <vector>
using namespace std;

template <
    class Key,
    class Data,
    class Compare = less<Key>,
    template <typename T> class Allocator = allocator
>
class mymap
{
public:
    typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap; 
    typedef vector<Data,Allocator<Data> > storageVector;
};

int main()
{
    mymap<int,long>::storageMap m;
    mymap<int,long>::storageVector v;
    return 0;
}

是的,它称为“模板模板参数”,其语法为

template <class Key, class Data, class Compare = less<Key>,
          template <typename T> class Allocator = allocator >
class mymap {
    typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap; 
    typedef vector<Data,Allocator<Data> > storageVector;
}

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