未在RewriteRule中传递ID

Question

我在使用.htaccess时遇到问题。重写规则如下。

RewriteRule ^user/([a-z]+)/?$ user.php?id=$1

传入的网址： http : //abhimanyu.localhost.com/user/home/其重定向到user.php，但我没有获取ID。 例如$ id = $ _GET ['id'];

知道为什么吗？

仅供参考

127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d34d28/subreq]
(1) [perdir
/home/administrator/public_html/abhimanyu/]
pass through
/home/administrator/public_html/abhimanyu/user.php
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(3) [perdir
/home/administrator/public_html/abhimanyu/]
add path info postfix:
/home/administrator/public_html/abhimanyu/user.php
-> /home/administrator/public_html/abhimanyu/user.php/home
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(3) [perdir
/home/administrator/public_html/abhimanyu/]
strip per-dir prefix:
/home/administrator/public_html/abhimanyu/user.php/home
-> user.php/home
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(3) [perdir
/home/administrator/public_html/abhimanyu/]
applying pattern '^user/([a-z]+)/?$'
to uri 'user.php/home'
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d21ce0/initial]
(1) [perdir
/home/administrator/public_html/abhimanyu/]
pass through
/home/administrator/public_html/abhimanyu/user.php
127.0.0.1 - - [08/May/2011:23:38:35 +051800] [abhimanyu.localhost.com/sid#b8b34860][rid#b8d2cd08/subreq]
(1) [perdir
/home/administrator/public_html/abhimanyu/]
pass through
/home/administrator/public_html/abhimanyu/home

Answer 1

尝试这个：

RewriteRule ^user/([a-z]+)$ user.php?id=$1 [NC]

Answer 2

我不知道您是要在/user/之后还是在/user/home之后立即捕获字符串。 如果您需要同时捕获两者，请尝试以下操作：

^user/([az]+)/(.+)$

您可以使用$1访问用户之后的第一个字符串，并使用$2访问第二个字符串。

Answer 3

尝试禁用MultiViews选项。