[英]Link to an item on a paginated page in php
我是PHP / MySQL的新手程序员。 我目前正在开发一个网站,并且找到了许多我在该网站上遇到的问题的答案-伟大的资源! -但是现在我要问一个自己正在挣扎的问题。 忍受我...
因此,在我的网站上,我有一个侧面板,该面板显示数据库中的推荐,并随机提取1个结果,以便每次用户浏览该网站时,展示的推荐都会发生变化。 侧面板是一个php include,并且在整个网站上显示。 我只展示几行推荐书,然后提供更多阅读链接。
在“个人鉴定”页面上,我有13个个人鉴定,每页(13页)每页1页,因为每个个人鉴定都相当长-这就是客户想要的。
我想做的是从“更多阅读”链接链接到相关推荐书-我认为使用html锚是最好的选择? 我发现的问题是我似乎无法链接到其分页页面上的相关项目。 如果我使用见证ID,则只能链接到testimonials.php的第1页,而不能链接到显示该见证的特定页面。 我希望这是有道理的?
我在侧面板以及“证明”页面上都包含了自己的代码副本。
任何见识或帮助将不胜感激。
谢谢。
Sidebar.php
$gettest = mysql_query ("SELECT * FROM testimonial ORDER BY RAND() LIMIT 1");
while ($row=mysql_fetch_array($gettest))
{
$testimonial = $row['testimonial'];
$shorttest = myTruncate($testimonial, 200, " ");
?>
<blockquote><span class="bqstart">“</span><p><?PHP echo $shorttest;?></p><span class="bqend">”</span></blockquote>
<p><a href="testimonials.php#<?PHP echo '' . $row["id"] . '';?>"><?PHP echo '' . $row["name"] . '';?></a></p>
<br clear='all' />
<?PHP
}
mysql_close($DB);
?>
见证.php
<?php
include('connectDB.php');
$tableName="testimonial";
$targetpage = "testimonials.php";
$limit = 1;
$query = "SELECT COUNT(*) as num FROM testimonial";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];
$stages = 3;
$page = mysql_escape_string($_GET['page']);
if($page){
$start = ($page - 1) * $limit;
}else{
$start = 0;
}
// Get page data
$query1 = "SELECT * FROM testimonial LIMIT $start, $limit";
$result = mysql_query($query1);
// Initial page num setup
if ($page == 0){$page = 1;}
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total_pages/$limit);
$LastPagem1 = $lastpage - 1;
$paginate = '';
if($lastpage > 1)
{
$paginate .= "<div class='paginate'>";
// Previous
if ($page > 1){
$paginate.= "<a href='$targetpage?page=$prev'>previous</a>";
}else{
$paginate.= "<span class='disabled'>previous</span>"; }
// Pages
if ($lastpage < 7 + ($stages * 2)) // Not enough pages to breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}
elseif($lastpage > 5 + ($stages * 2)) // Enough pages to hide a few?
{
// Beginning only hide later pages
if($page < 1 + ($stages * 2))
{
for ($counter = 1; $counter < 4 + ($stages * 2); $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}
// Middle hide some front and some back
elseif($lastpage - ($stages * 2) > $page && $page > ($stages * 2))
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $page - $stages; $counter <= $page + $stages; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}
// End only hide early pages
else
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $lastpage - (2 + ($stages * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}
}
// Next
if ($page < $counter - 1){
$paginate.= "<a href='$targetpage?page=$next'>next</a>";
}else{
$paginate.= "<span class='disabled'>next</span>";
}
$paginate.= "</div>";
}
// pagination
echo $paginate;
?>
<?php
while($row = mysql_fetch_array($result))
{
?>
<a name="<?PHP echo '' . $row["ID"] . '';?>"></a>
<blockquote><span class="bqstart">“</span><p><?PHP echo '' .nl2br($row["testimonial"]) . '';?></p><span class="bqend">”</span></blockquote>
<p class="highlight"><?PHP echo '' . $row["name"] . '';?></p>
<br clear='all' />
<?PHP
}
echo $paginate;
mysql_close($DB);
?>
我现在不打算对代码进行所有更改,因为现在很乱。
您可能迷失了自己的代码。
只需将这一行(在sidebar.php上)更改为:
<p><a href="testimonials.php?page=<?PHP echo '' . $row["id"] . '';?>"><?PHP echo '' . $row["name"] . '';?></a></p>
(类似于您在“ Testimonials.php”页面上所做的操作。)
这样的事情:
<?php
$gettest = mysql_query ("SELECT * FROM testimonial ORDER BY RAND() LIMIT 1");
while ($row=mysql_fetch_array($gettest))
{
$testimonial = $row['testimonial'];
$shorttest = myTruncate($testimonial, 200, " ");
?>
<blockquote><span class="bqstart">“</span><p><?PHP echo $shorttest;?></p><span class="bqend">”</span></blockquote>
<p><a href="testimonials.php?testimonialid=<?PHP echo '' . $row["id"] . '';?>"><?PHP echo '' . $row["name"] . '';?></a></p>
<br clear='all' />
<?PHP
}
mysql_close($DB);
?>
和
<?php
include('connectDB.php');
$query = "SELECT COUNT(*) as num FROM testimonial";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];
$testimonialid = mysql_escape_string($_GET['testimonialid']);
// Get page data
$query1 = "SELECT * FROM testimonial WHERE id = ".$testimonialid;
$result = mysql_query($query1);
$paginate = '';
if($total_pages > $testimonialid)
{
$paginate .= '<a href="testimonials.php?testimonialid='.($testimonialid+1).'">next</a>';
}
if($testimonialid > 1)
{
$paginate .= '<a href="testimonials.php?testimonialid='.($testimonialid-1).'">previous</a>';
}
?>
<?php
echo $paginate;
while($row = mysql_fetch_array($result))
{
?>
<a name="<?PHP echo '' . $row["ID"] . '';?>"></a>
<blockquote><span class="bqstart">“</span><p><?PHP echo '' .nl2br($row["testimonial"]) . '';?></p><span class="bqend">”</span></blockquote>
<p class="highlight"><?PHP echo '' . $row["name"] . '';?></p>
<br clear='all' />
<?php
}
echo $paginate;
mysql_close($DB);
?>
我删除了大多数分页代码,但这只是向您展示如何实现它。
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