iOS 上的电话号码格式

Question

我有一个文本字段，用户可以在其中输入数据。 这是一个电话号码字段。 如果用户输入1234567890 ，我希望它在用户输入时显示为(123)-(456)-7890 。 这怎么可能？

Answer 1

这会对你有所帮助

格式（xxx）xxx-xxxx

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
    int length = (int)[self getLength:textField.text];
    //NSLog(@"Length  =  %d ",length);

    if(length == 10)
    {
        if(range.length == 0)
            return NO;
    }

    if(length == 3)
    {
        NSString *num = [self formatNumber:textField.text];
        textField.text = [NSString stringWithFormat:@"(%@) ",num];

        if(range.length > 0)
            textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
    }
    else if(length == 6)
    {
        NSString *num = [self formatNumber:textField.text];
        //NSLog(@"%@",[num  substringToIndex:3]);
        //NSLog(@"%@",[num substringFromIndex:3]);
        textField.text = [NSString stringWithFormat:@"(%@) %@-",[num  substringToIndex:3],[num substringFromIndex:3]];

        if(range.length > 0)
            textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
    }

    return YES;
}

- (NSString *)formatNumber:(NSString *)mobileNumber
{
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    NSLog(@"%@", mobileNumber);

    int length = (int)[mobileNumber length];
    if(length > 10)
    {
        mobileNumber = [mobileNumber substringFromIndex: length-10];
        NSLog(@"%@", mobileNumber);

    }

    return mobileNumber;
}

- (int)getLength:(NSString *)mobileNumber
{
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    int length = (int)[mobileNumber length];

    return length;
}

Answer 2

这感觉更清晰，处理更好的删除任何不需要的字符。 正确格式为1（###）### - ####或（###）### - ####

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
    NSString *newString = [textField.text stringByReplacingCharactersInRange:range withString:string];
    NSArray *components = [newString componentsSeparatedByCharactersInSet:[[NSCharacterSet decimalDigitCharacterSet] invertedSet]];
    NSString *decimalString = [components componentsJoinedByString:@""];

    NSUInteger length = decimalString.length;
    BOOL hasLeadingOne = length > 0 && [decimalString characterAtIndex:0] == '1';

    if (length == 0 || (length > 10 && !hasLeadingOne) || (length > 11)) {
        textField.text = decimalString;
        return NO;
    }

    NSUInteger index = 0;
    NSMutableString *formattedString = [NSMutableString string];

    if (hasLeadingOne) {
        [formattedString appendString:@"1 "];
        index += 1;
    }

    if (length - index > 3) {
        NSString *areaCode = [decimalString substringWithRange:NSMakeRange(index, 3)];
        [formattedString appendFormat:@"(%@) ",areaCode];
        index += 3;
    }

    if (length - index > 3) {
        NSString *prefix = [decimalString substringWithRange:NSMakeRange(index, 3)];
        [formattedString appendFormat:@"%@-",prefix];
        index += 3;
    }

    NSString *remainder = [decimalString substringFromIndex:index];
    [formattedString appendString:remainder];

    textField.text = formattedString;

    return NO;
}

Answer 3

下面的代码是我通常使用的代码。 格式不同但你得到的图片。 这将处理诸如'123df＃$ @ $ gdfg45- + 678dfg901'和输出'1（234）567-8901'之类的输入

#import "NSString+phoneNumber.h"

@implementation NSString (phoneNumber)

-(NSString*) phoneNumber{
    static NSCharacterSet* set = nil;
    if (set == nil){
        set = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];
    }
    NSString* phoneString = [[self componentsSeparatedByCharactersInSet:set] componentsJoinedByString:@""];
    switch (phoneString.length) {
        case 7: return [NSString stringWithFormat:@"%@-%@", [phoneString substringToIndex:3], [phoneString substringFromIndex:3]];
        case 10: return [NSString stringWithFormat:@"(%@) %@-%@", [phoneString substringToIndex:3], [phoneString substringWithRange:NSMakeRange(3, 3)],[phoneString substringFromIndex:6]];
        case 11: return [NSString stringWithFormat:@"%@ (%@) %@-%@", [phoneString substringToIndex:1], [phoneString substringWithRange:NSMakeRange(1, 3)], [phoneString substringWithRange:NSMakeRange(4, 3)], [phoneString substringFromIndex:7]];
        case 12: return [NSString stringWithFormat:@"+%@ (%@) %@-%@", [phoneString substringToIndex:2], [phoneString substringWithRange:NSMakeRange(2, 3)], [phoneString substringWithRange:NSMakeRange(5, 3)], [phoneString substringFromIndex:8]];
        default: return nil;
    }
}

@end

Answer 4

我们在这里为电话号码写了一个自定义的NSFormatter子类： https ： //github.com/edgecase/PhoneNumberFormatter

您可以像使用任何其他NSFormatter子类一样使用它。

Answer 5

非常感谢第一个答案，但是，我想，那个方法-(int)getLength:(NSString*)mobileNumber是没用的。 您可以尝试以下内容：

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{

int length = [[self formatNumber:[textField text]] length];

if (length == 10) {
    if(range.length == 0) {
        return NO;
    }
}

if (length == 3) {
    NSString *num = [self formatNumber:[textField text]];
    textField.text = [NSString stringWithFormat:@"(%@) ",num];
    if (range.length > 0) {
        [textField setText:[NSString stringWithFormat:@"%@",[num substringToIndex:3]]];
    }
}
else if (length == 6) {
    NSString *num = [self formatNumber:[textField text]];
    [textField setText:[NSString stringWithFormat:@"(%@) %@-",[num  substringToIndex:3],[num substringFromIndex:3]]];
    if (range.length > 0) {
        [textField setText:[NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]]];
    }
}

return YES;
}

- (NSString*)formatNumber:(NSString*)mobileNumber {
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

int length = [mobileNumber length];

if (length > 10) {
    mobileNumber = [mobileNumber substringFromIndex: length-10];
}

return mobileNumber;
}

Answer 6

对于那些需要国际号码格式的人： https ： //code.google.com/p/libphonenumber/

附带C ++，Java和JavaScript实现。 应该很容易将C ++实现包装在.mm文件中并围绕它编写一个小的Objective-C包装器。

Answer 7

也许你可以使用这个简单的方法：

+ (NSString*) formatPhoneNumber:(NSString *)phoneNumber codeLength:(int) code segmentLength:(int) segment
{
    NSString* result = @"";

    int length = [phoneNumber length];

    NSString* firstSegment = @"";
    NSString* restSegment = @"";

    for (int i=0; i<length; i++) {

        char c = [phoneNumber characterAtIndex:i];

        if(i < code)
            firstSegment = [firstSegment stringByAppendingFormat:@"%c", c];
        else
        {
            restSegment = [restSegment stringByAppendingFormat:@"%c", c];

            int threshold = (i - code) + 1;

            if((threshold % segment == 0) && (threshold > 0) && !(threshold > length))
                restSegment = [restSegment stringByAppendingFormat:@"%c", '-'];
        }

    }

    result = [result stringByAppendingFormat:@"%@-%@", firstSegment, restSegment];

    return result;
}

假设上面的方法在Contact类中，只需使用如下方法：

NSString* phoneNumber = @"085755023455";

NSString* formattedNumber = [Contact formatPhoneNumber:phoneNumber codeLength:3 segmentLength:4];

这将产生如下结果：

085-7550-2345-5

Answer 8

有效选项是https://github.com/iziz/libPhoneNumber-iOS所有其他答案仅涵盖可能性和组合的一小部分，该库实际上解析并验证每个电话号码，并确定：

• 国籍
• 电话号码类型
• 国家承运人

Answer 9

与美国电话号码相关：

添加到@ wan的帖子，如果用户以国家代码（1）开头，我添加了一个条件语句。 这样，它将格式化为：1（XXX）XXX-XXXX而不是（1XX）XXX-XXXX。

    - (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{
    textField = self.phoneNumberTextField;

    NSInteger length = [self getLength:textField.text];
    //NSLog(@"Length  =  %d ",length);

    if ([textField.text hasPrefix:@"1"]) {
        if(length == 11)
        {
            if(range.length == 0)
                return NO;
        }
        if(length == 4)
        {
            NSString *num = [self formatNumber:textField.text];
            textField.text = [NSString stringWithFormat:@"%@ (%@) ",[num substringToIndex:1],[num substringFromIndex:1]];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:4]];
        }
        else if(length == 7)
        {
            NSString *num = [self formatNumber:textField.text];
            NSRange numRange = NSMakeRange(1, 3);
            textField.text = [NSString stringWithFormat:@"%@ (%@) %@-",[num substringToIndex:1] ,[num substringWithRange:numRange],[num substringFromIndex:4]];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
        }

    } else {
        if(length == 10)
        {
            if(range.length == 0)
                return NO;
        }

        if(length == 3)
        {
            NSString *num = [self formatNumber:textField.text];
            textField.text = [NSString stringWithFormat:@"(%@) ",num];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
        }
        else if(length == 6)
        {
            NSString *num = [self formatNumber:textField.text];

            textField.text = [NSString stringWithFormat:@"(%@) %@-",[num  substringToIndex:3],[num substringFromIndex:3]];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
        }
    }
    return YES;
}

-(NSString*)formatNumber:(NSString*)mobileNumber
{
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    NSLog(@"%@", mobileNumber);

    NSInteger length = [mobileNumber length];
    if(length > 10)
    {
        mobileNumber = [mobileNumber substringFromIndex: length-10];
        NSLog(@"%@", mobileNumber);

    }


    return mobileNumber;
}
-(NSInteger)getLength:(NSString*)mobileNumber
{

    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    NSInteger length = [mobileNumber length];

    return length;        
}

Answer 10

您可以使用AKNumericFormatter库。 它具有格式化和方便的UITextField类别，它可以作为cocoapod使用。

Answer 11

关于如何在iOS中进行手机格式化的C＃Xamarin.iOS版本最全面的答案如下

    public override void ViewDidLoad()
    {
        base.ViewDidLoad();
        PhoneNumberTextField.ShouldChangeCharacters = ChangeCharacters;
    }

    private bool ChangeCharacters(UITextField textField, NSRange range, string replacementString)
    {
        var text = textField.Text;
        var newString = text.Substring(0, range.Location) + replacementString + text.Substring(range.Location + range.Length);
        var decimalString = Regex.Replace(newString, @"[^\d]", string.Empty);
        var length = decimalString.Length;
        var hasLeadingOne = length > 0 && decimalString[0] == '1';
        if ((length == 0) || (length > 10 && !hasLeadingOne) || (length > 11))
        {
            textField.Text = decimalString;
            return false;
        }
        var index = 0;
        var formattedString = "";
        if (hasLeadingOne)
        {
            formattedString += "1";
            index += 1;
        }
        if (length - index > 3)
        {
            var areaCode = decimalString.Substring(index, 3);
            formattedString += "(" + areaCode + ")";
            index += 3;
        }
        if (length - index > 3)
        {
            var prefix = decimalString.Substring(index, 3);
            formattedString += " " + prefix + "-";
            index += 3;
        }
        var remainder = decimalString.Substring(index);
        formattedString += remainder;
        textField.Text = formattedString;
        return false;
    }

Answer 12

迅速

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {        
            let length = self.getTextLength(textField.text)



            if length == 10{
                if range.length == 0{
                    return false
                }
            }

            if length == 3{

                var num : String = self.formatNumber(textField.text)

                textField.text = num + "-"
                if(range.length > 0){
                    textField.text = (num as NSString).substringToIndex(3)
                }
            }
            else if length == 6{

                var num : String = self.formatNumber(textField.text)

                let prefix  = (num as NSString).substringToIndex(3)
                let postfix = (num as NSString).substringFromIndex(3)

                textField.text = prefix + "-" + postfix + "-"

                if range.length > 0{
                    textField.text = prefix + postfix
                }
            }

            return true
    }




func getTextLength(mobileNo: String) -> NSInteger{

        var str : NSString = mobileNo as NSString
        str = str.stringByReplacingOccurrencesOfString("(", withString: "")
        str = str.stringByReplacingOccurrencesOfString(")", withString: "")
        str = str.stringByReplacingOccurrencesOfString(" ", withString: "")
        str = str.stringByReplacingOccurrencesOfString("-", withString: "")
        str = str.stringByReplacingOccurrencesOfString("+", withString: "")

        return str.length
    }

    func formatNumber(mobileNo: String) -> String{
        var str : NSString = mobileNo as NSString
        str = str.stringByReplacingOccurrencesOfString("(", withString: "")
        str = str.stringByReplacingOccurrencesOfString(")", withString: "")
        str = str.stringByReplacingOccurrencesOfString(" ", withString: "")
        str = str.stringByReplacingOccurrencesOfString("-", withString: "")
        str = str.stringByReplacingOccurrencesOfString("+", withString: "")

        if str.length > 10{
            str = str.substringFromIndex(str.length - 10)
        }

        return str as String
    }

Answer 13

Swift格式化的电话号码

改进oppon @ datinc的答案，输入如1123df#$@$gdfg45-+678dfg901将输出为+11(234)567-8901

func formattedPhone(phone: String) -> String?  {
    let notPhoneNumbers = NSCharacterSet.decimalDigitCharacterSet().invertedSet
    let str = phone.componentsSeparatedByCharactersInSet(notPhoneNumbers).joinWithSeparator("")

    let startIdx = str.startIndex
    let endIdx = str.endIndex

    let count = str.characters.count
    if count == 7 {
        return "\(str[startIdx..<startIdx.advancedBy(3)])-\(str[startIdx.advancedBy(3)..<endIdx])"
    }else if count == 10{
        return "(\(str[startIdx..<startIdx.advancedBy(3)]))\(str[startIdx.advancedBy(3)..<startIdx.advancedBy(6)])-\(str[startIdx.advancedBy(6)..<endIdx])"
    }
    else if count > 10{
        let extra = str.characters.count - 10
        return "+\(str[startIdx..<startIdx.advancedBy(extra)])(\(str[endIdx.advancedBy(-10)..<endIdx.advancedBy(-7)]))\(str[endIdx.advancedBy(-7)..<endIdx.advancedBy(-4)])-\(str[endIdx.advancedBy(-4)..<endIdx])"
    }
    return nil
}

Answer 14

这会对你有所帮助

格式（xxx）xxx-xxxx适用于SWIFT 3.0

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
        let length = Int(getLength(mobileNumber: textField.text!))

        if length == 15 {
            if range.length == 0 {
                return false
            }
        }

        if length == 3 {

            let num = self.formatNumber(mobileNumber: textField.text!)

            textField.text = NSString(format:"(%@)",num) as String

            if range.length > 0{
                let index: String.Index = num.index(num.startIndex, offsetBy: 3)
                textField.text = NSString(format:"%@",num.substring(to: index)) as String
            }

        }else if length == 6 {
            let num = self.formatNumber(mobileNumber: textField.text!)
            let index: String.Index = num.index(num.startIndex, offsetBy: 3)

            textField.text = NSString(format:"(%@) %@-",num.substring(to: index), num.substring(from: index)) as String
            if range.length > 0{
                textField.text = NSString(format:"(%@) %@",num.substring(to: index), num.substring(from: index)) as String
            }
        }

        return true
    }

    func formatNumber(mobileNumber: String) -> String {
        var number = mobileNumber
        number = number.replacingOccurrences(of: "(", with: "")
        number = number.replacingOccurrences(of: ")", with: "")
        number = number.replacingOccurrences(of: " ", with: "")
        number = number.replacingOccurrences(of: "-", with: "")
        number = number.replacingOccurrences(of: "+", with: "")

        let length = Int(number.characters.count)

        if length > 15 {
            let index = number.index(number.startIndex, offsetBy: 15)

           number = number.substring(to: index)
        }

        return number
    }

    func getLength(mobileNumber: String) -> Int {

        var number = mobileNumber
        number = number.replacingOccurrences(of: "(", with: "")
        number = number.replacingOccurrences(of: ")", with: "")
        number = number.replacingOccurrences(of: " ", with: "")
        number = number.replacingOccurrences(of: "-", with: "")
        number = number.replacingOccurrences(of: "+", with: "")

        let length = Int(number.characters.count)
        return length

    }

Answer 15

所以这个方法格式为（xxx）xxx - xxxx ....
它是对当前最佳答案的修改并处理退格

- (IBAction)autoFormat:(UITextField *)sender {

NSString *mobileNumber = [NSString stringWithFormat:@"%@",sender.text];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

int length = [mobileNumber length];
if(length > 0 && [sender.text length] > self.oldLength){
    if(length >= 7 && length <= 10){
        sender.text = [NSString stringWithFormat:@"(%@) %@ - %@",[mobileNumber substringToIndex:3], [mobileNumber substringWithRange:NSMakeRange(3,3)],[mobileNumber substringWithRange:NSMakeRange(6,[mobileNumber length]-6)]];
    } else if(length >= 4 && length <= 6) {
        sender.text = [NSString stringWithFormat:@"(%@) %@",[mobileNumber substringToIndex:3], [mobileNumber substringWithRange:NSMakeRange(3,[mobileNumber length]-3)]];
    }
    if(length >= 11 && length % 4 == 3){
        NSString *lastChar = [sender.text substringFromIndex:[sender.text length] - 1];
        sender.text = [NSString stringWithFormat:@"%@ %@",[sender.text substringToIndex:[sender.text length] - 1],lastChar];
    }
    self.oldLength = [sender.text length];
} else if([sender.text length] < self.oldLength) {
    NSLog(@"deleted - ");
    self.oldLength = 0;

    sender.text = @"";
    for (int i = 0; i < [mobileNumber length]; i = i + 1) {
        sender.text = [NSString stringWithFormat:@"%@%@",sender.text,[mobileNumber substringWithRange:NSMakeRange(i, 1)]];
        [self autoFormat:sender];
    }
}}

希望能帮助到你

Answer 16

REFormattedNumberField可能是最好的。 只需提供您想要的格式。

Answer 17

另外对于格式+ x（xxx）xxx-xx-xx，您可以使用类似这样简单的解决方案：

+ (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
NSString *newString = [textField.text stringByReplacingCharactersInRange:range withString:string];
NSArray *components = [newString componentsSeparatedByCharactersInSet:[[NSCharacterSet decimalDigitCharacterSet] invertedSet]];
NSString *decimalString = [components componentsJoinedByString:@""];

if (decimalString.length > 11) {
    return NO;
}

NSMutableString *formattedString = [NSMutableString stringWithString:decimalString];

[formattedString insertString:@"+" atIndex:0];

if (formattedString.length > 2)
    [formattedString insertString:@" (" atIndex:2];

if (formattedString.length > 7)
    [formattedString insertString:@") " atIndex:7];

if (formattedString.length > 12)
    [formattedString insertString:@"-" atIndex:12];

if (formattedString.length > 15)
    [formattedString insertString:@"-" atIndex:15];


textField.text = formattedString;
return NO;}      

Answer 18

+(NSString *) phoneNumberFormatterTextField:(NSString *)number forRange:(NSRange)range
{
    int length = (int)[[self getPhoneNumber:number] length];
    if(length == 3)
    {
        NSString *num = [MPosBaseScreenController getPhoneNumber:number];
        number = [num stringByReplacingOccurrencesOfString:@"(\\d{3})"
                                              withString:@"($1) "
                                                 options:NSRegularExpressionSearch
                                                   range:NSMakeRange(0, num.length)];

    }
    else if(length == 6 || length > 6 )
    {
        NSString *num = [MPosBaseScreenController getPhoneNumber:number];
        number = [num stringByReplacingOccurrencesOfString:@"(\\d{3})(\\d{3})"
                                              withString:@"($1) $2 - "
                                                 options:NSRegularExpressionSearch
                                                   range:NSMakeRange(0, num.length)];
    }
       return number;
}

Answer 19

这是一个简单的类别，它将模仿输入的格式

@interface NSString (formatDecimalsAs)
- (NSString *)formatDecimalsAs:(NSString *)formattedDecimals;
@end

@implementation NSString (formatDecimalsAs)
- (NSString *)formatDecimalsAs:(NSString *)formattedDecimals
{
    // insert non-digit characters from source string
    NSMutableString *formattedNumber = [self mutableCopy];
    for (int i = 0; i < formattedDecimals.length; i++)
    {
        if (i > formattedNumber.length)
        {
            break;
        }
        unichar character = [formattedDecimals characterAtIndex:i];
        if ([[NSCharacterSet decimalDigitCharacterSet].invertedSet characterIsMember:character])
        {
            [formattedNumber insertString:[NSString stringWithFormat:@"%c", character] atIndex:(NSUInteger) i];
        }
    }
    return formattedNumber;
}
@end

示例使用

[@"87654321" formatDecimalsAs:@"1111 1111"] // returns @"8765 4321"

Answer 20

1. 删除所有非数字字符
2. 如果剩下7位数，则为123-4567
3. 10位数，（123）456-7890

4. 否则，三人一组。 要调整组的大小，请更改分配给substrsize的值

    -(NSString*)formatPhone:(NSString*)phone { NSString *formattedNumber = [[phone componentsSeparatedByCharactersInSet: [[NSCharacterSet decimalDigitCharacterSet] invertedSet]] componentsJoinedByString:@""]; int substrSize = 3; NSMutableArray *t = [[NSMutableArray alloc] initWithCapacity:formattedNumber.length / substrSize + 1]; switch (formattedNumber.length) { case 7: formattedNumber = [NSString stringWithFormat:@"%@-%@", [formattedNumber substringToIndex:3], [formattedNumber substringFromIndex:3]]; break; case 10: formattedNumber = [NSString stringWithFormat:@"(%@) %@-%@", [formattedNumber substringToIndex:3], [formattedNumber substringWithRange:NSMakeRange(3, 3)], [formattedNumber substringFromIndex:6]]; break; default: for (int i = 0; i < formattedNumber.length / substrSize; i++) { [t addObject:[formattedNumber substringWithRange:NSMakeRange(i * substrSize, substrSize)]]; } if (formattedNumber.length % substrSize) { [t addObject:[formattedNumber substringFromIndex:(substrSize * t.count)]]; } formattedNumber = [t componentsJoinedByString:@" "]; break; } return formattedNumber; } 

Answer 21

在SWIFT 3中

func formattedPhone(phone: String) -> String?  {
    let notPhoneNumbers = CharacterSet.decimalDigits.inverted
    let str = phone.components(separatedBy: notPhoneNumbers).joined(separator: "")

    let startIdx = str.startIndex
    let endIdx = str.endIndex

    let count = str.characters.count
    if count == 7 {
        return "\(str[startIdx..<startIdx.advance(3, for: str)])-\(str[startIdx.advance(3, for: str)..<endIdx])"
    }else if count == 10{
        return "+1 (\(str[startIdx..<startIdx.advance(3, for: str)])) \(str[startIdx.advance(3, for: str)..<startIdx.advance(6, for: str)])-\(str[startIdx.advance(6, for: str)..<endIdx])"
    }
    else if count > 10{
        let extra = str.characters.count - 10
        return "+\(str[startIdx..<startIdx.advance(extra, for: str)]) (\(str[endIdx.advance(-10, for: str)..<endIdx.advance(-7, for: str)])) \(str[endIdx.advance(-7, for: str)..<endIdx.advance(-4, for: str)])-\(str[endIdx.advance(-4, for: str)..<endIdx])"
    }
    return nil
}

Swift 3 string.index.advancedBy（3）替代：

extension String.Index{
func advance(_ offset:Int, `for` string:String)->String.Index{
    return string.index(self, offsetBy: offset)
}
}

Answer 22

首先，将UITextFieldDelegate添加到.h文件中，并在nib文件中委派您的UITextField 。

其次，将此代码添加到.m文件中：

    - (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
        {
            NSString *filter = @"(###)-(###)-####";

            if(!filter) return YES;

            NSString *changedString = [textField.text stringByReplacingCharactersInRange:range withString:string];

            if(range.length == 1 && 
               string.length < range.length &&
               [[textField.text substringWithRange:range] rangeOfCharacterFromSet:[NSCharacterSet characterSetWithCharactersInString:@"0123456789"]].location == NSNotFound)
            {

                NSInteger location = changedString.length-1;
                if(location > 0)
                {
                    for(; location > 0; location--)
                    {
                        if(isdigit([changedString characterAtIndex:location]))
                        {
                            break;
                        }
                    }
                    changedString = [changedString substringToIndex:location];
                }
            }

            textField.text = [self filteredPhoneStringFromStringWithFilter:changedString :filter];

            return NO;

        }

    -(NSString*) filteredPhoneStringFromStringWithFilter:(NSString*)number : (NSString*)filter{
        NSUInteger onOriginal = 0, onFilter = 0, onOutput = 0;
        char outputString[([filter length])];
        BOOL done = NO;

    while(onFilter < [filter length] && !done)
    {
        char filterChar = [filter characterAtIndex:onFilter];
        char originalChar = onOriginal >= number.length ? '\0' : [number characterAtIndex:onOriginal];
        switch (filterChar) {
            case '#':
                if(originalChar=='\0')
                {
                    // We have no more input numbers for the filter.  We're done.
                    done = YES;
                    break;
                }
                if(isdigit(originalChar))
                {
                    outputString[onOutput] = originalChar;
                    onOriginal++;
                    onFilter++;
                    onOutput++;
                }
                else
                {
                    onOriginal++;
                }
                break;
            default:
                // Any other character will automatically be inserted for the user as they type (spaces, - etc..) or deleted as they delete if there are more numbers to come.
                outputString[onOutput] = filterChar;
                onOutput++;
                onFilter++;
                if(originalChar == filterChar)
                    onOriginal++;
                break;
        }
    }
    outputString[onOutput] = '\0'; // Cap the output string
    return [NSString stringWithUTF8String:outputString];
}

Answer 23

NSString *str=@"[+]+91[0-9]{10}";
NSPredicate *no=[NSPredicate predicateWithFormat:@"SELF MATCHES %@",str];
if([no evaluateWithObject:txtMobileno.text]==NO
{ 
    UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"Warning" message:@"Please Enter correct contact no." delegate:self cancelButtonTitle:@"ok" otherButtonTitles:nil];

    [alert show];
    [alert release];    
}

Answer 24

对于格式为“X”的掩码（如“(XXX) XXX XXXX”）

NSString* formatPhoneNumber(NSString* phoneNumber, NSString *mask) {
    // Remove any non-numeric characters from the phone number string
    NSString* strippedNumber = [[phoneNumber componentsSeparatedByCharactersInSet:
                                [[NSCharacterSet decimalDigitCharacterSet] invertedSet]]
                               componentsJoinedByString:@""];
    // Check if the phone number is the correct length
    if (strippedNumber.length != [mask componentsSeparatedByString:@"X"].count) {
        return phoneNumber;
    }
    // Initialize a string for the formatted phone number
    NSString* formattedNumber = mask;
    int i = 0;
    // Iterate through the mask, replacing "X" with corresponding digits
    for (NSUInteger j = 0; j < formattedNumber.length; j++) {
        if ([formattedNumber characterAtIndex:j] == 'X') {
            formattedNumber = [formattedNumber stringByReplacingCharactersInRange:NSMakeRange(j, 1) withString:[strippedNumber substringWithRange:NSMakeRange(i, 1)]];
            i++;
        }
    }
    return formattedNumber;
}