[英]MySQL single table, select value based on multiple rows
从下表中,我将如何 select 所有具有attributeIds 特定组合的animalIds 例如,如果我提供attributeIds 455 和685 我希望得到animalIds 55 和93
表名:animalAttributes
id attributeId animalId
1 455 55
2 233 55
3 685 55
4 999 89
5 455 89
6 333 93
7 685 93
8 455 93
我有以下查询似乎有效,但是,我不确定是否有更强大的方法?
SELECT animalId
FROM animalAttributes
WHERE attributeId IN (455,685)
GROUP BY animalId
HAVING COUNT(DISTINCT attributeId) = 2;
SELECT DISTINCT animalId
FROM animalAttributes
WHERE attributeId IN (455,685)
或者
SELECT animalId
FROM animalAttributes
WHERE attributeId IN (455,685)
GROUP BY animalId
如果你真的想要准确的结果,你可以 go 使用这样的万无一失的方法:
select distinct base.animalId
from animalAttributes base
join animalAttributes a on base.animalId = a.animalId
and a.attributeId = 455
where base.attributeId = 685
如果您以后需要 3 个匹配的属性,您可以添加另一个联接:
select distinct base.animalId
from animalAttributes base
join animalAttributes a on base.animalId = a.animalId
and a.attributeId = 455
join animalAttributes b on base.animalId = b.animalId
and b.attributeId = 999
where base.attributeId = 685
SELECT DISTINCT `animalId` FROM `animalAttributes` WHERE `attributeId` = 455
INTERSECT
SELECT DISTINCT `animalId` FROM `animalAttributes` WHERE `attributeId` = 685
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