[英]How to parse XML contained in a string to an IList<BusinessObject>?
[英]How to parse XML to an IList<BusinessObject> using XPath in C#?
我在字符串中有以下 XML :
<RootElement>
<Data>
<Row>
<Id>1</Id>
<Name>Foo</Name>
</Row>
<Row>
<Id>2</Id>
<Name>Bar</Name>
</Row>
</Data>
</RootElement>
以及以下 class:
public class BusinessObject
{
public int Id { get; set; }
public string Name { get; set; }
}
如何使用 XPath 将 Row 元素中的所有数据解析为 IList?
我需要学习这个以进行培训。
感谢您的回答。
IEnumerable<BusinessObject> ParseWithXPath(string xml)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach (XmlNode node in doc.DocumentElement.SelectNodes("Data/Row")) // XPath query
{
yield return new BusinessObject
{
Id = Int32.Parse(node.SelectSingleNode("Id").InnerText),
Name = node.SelectSingleNode("Name").InnerText
};
}
}
用法:
IEnumerable<BusinessObject> seq = ParseWithXPath(xml); // .NET 2.0+
IList<BusinessObject> list = new List<BusinessObject>(seq); // .NET 2.0+
当我为您编写示例时,我看到您已经找到了一个相当干净的解决方案。
也许这对您有更多帮助:
internal static class XMLToListWithXPathExample
{
static XmlDocument xmlDocument;
static List<BusinessObject> listBusinessObjects;
static string sXpathStatement = "/Data/Row";
static void LoadXMLData(string p_sXMLDocumentPath)
{
xmlDocument = new XmlDocument(); // setup the XmlDocument
xmlDocument.Load(p_sXMLDocumentPath); // load the Xml data
}
static void XMLDocumentToList()
{
listBusinessObjects = new List<BusinessObject>(); // setup the list
foreach (XmlNode xmlNode in xmlDocument.SelectNodes(sXpathStatement)) // loop through each node
{
listBusinessObjects.Add( // and add it to the list
new BusinessObject(
int.Parse(xmlNode.SelectSingleNode("Id").InnerText), // select the Id node
xmlNode.SelectSingleNode("Name").InnerText)); // select the Name node
}
}
}
public class BusinessObject
{
public int Id { get; set; }
public string Name { get; set; }
// constructor
public BusinessObject(int p_iID, string p_sName)
{
Id = p_iID;
Name = p_sName;
}
}
问候,尼科
IEnumerable<BusinessObject> busObjects = from item in doc.Descendants("Row")
select new BusinessObject((int)item.Element("Id"), (string)item.Element("Name"));
你可以试试上面的方法。 您的 BusinessObject 构造函数应采用这两个参数。 BusinessObject(int id, string name)
请查看以下链接,例如 Linq 到 XML。
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