MySQL：使用来自查询的信息创建新表

Question

在 MySQL 中，我想创建一个包含此查询中所有信息的新表：

select * into consultaa2 from SELECT
 CONCAT(    'UPDATE customers SET
 customers_default_address_id= ',    
 (SELECT a.address_book_id FROM
 address_book a where
 c.customers_id=a.customers_id order by
 address_book_id desc limit 1),    '
 WHERE customers_id = ', customers_id,
 ';') AS sql_statement FROM customers c
 where c.customers_id > 3894;

查询太长，浏览器无法显示 concat，我需要它来进行更新。

Answer 1

你可以这样做：

CREATE TABLE tablename SELECT * FROM othertable;

tablename是您要创建的新表的名称， SELECT * FROM othertable是返回应创建表的数据的查询。

Answer 2

*请注意，此方法不会创建表（根据 OP 标题）。 为此，请参阅此答案。 *

---

使用来自查询的信息插入到表中的格式为

INSERT INTO <TABLE-1> 
SELECT * FROM <TABLE-2>

在你的情况下，这将是

insert into consultaa2 
SELECT CONCAT( 'UPDATE customers SET customers_default_address_id= ',
(SELECT a.address_book_id FROM address_book a where c.customers_id=a.customers_id order by address_book_id desc limit 1), ' WHERE customers_id = ', customers_id, ';') AS sql_statement FROM customers c where c.customers_id > 3894;

只需确保要插入的表中的列与从 select 查询返回的列匹配即可。

Answer 3

mysql 创建新表

mysql 命令行示例。

mysql> create table foo(id int, vorta text);
Query OK, 0 rows affected (0.02 sec)

插入行

mysql> insert into foo values(1, 'for the hoarde');
Query OK, 1 row affected (0.00 sec)

看看里面有什么

mysql> select * from foo;
+------+----------------+
| id   | vorta          |
+------+----------------+
|    1 | for the horde  |
+------+----------------+
1 row in set (0.00 sec)

使用来自查询的信息创建一个新表

mysql> create table foo2 select * from foo;
Query OK, 1 row affected (0.01 sec)
Records: 1  Duplicates: 0  Warnings: 0

检查数据是否移动

mysql> select * from foo2;
+------+----------------+
| id   | vorta          |
+------+----------------+
|    1 | for the horde  |
+------+----------------+
1 row in set (0.00 sec)