[英]How to remove a line from a file by knowing its position?
我想从我的文件中删除一行(特别是第二行),所以我使用了另一个文件来复制它,但是使用以下代码,第二个文件包含完全相同的文本。(我的原始 file.txt 和我的最终文件.xml)
public static File fileparse() throws SQLException, FileNotFoundException, IOException {
File f=fillfile();//my original file
dostemp = new DataOutputStream(new FileOutputStream(filetemp));
int lineremove=1;
while (f.length()!=0) {
if (lineremove<2) {
read = in.readLine();
dostemp.writeBytes(read);
lineremove++;
}
if (lineremove==2) {
lineremove++;
}
if (lineremove>2) {
read = in.readLine();
dostemp.writeBytes(read);
}
}
return filetemp;
}
如果lineremove
为 2,则您不会读取该行,并且您在它为 2 时增加它之后检查它是否大于 2。这样做:
int line = 1;
String read = null;
while((read = in.readLine()) != null){
if(line!=2)
{
dostemp.writeBytes(read);
}
line++;
}
您可以使用带有readLine()
方法的BufferedReader
逐行读取,检查它是否是您想要的行并跳过您不想要的行。
检查文档: BufferedReader
这是一个工作示例(不是最漂亮或最干净的:)):
public static void main(String[] args) {
// TODO Auto-generated method stub
BufferedReader in = null;
try {
in = new BufferedReader(new FileReader("d:\\test.txt"));
} catch (FileNotFoundException e3) {
// TODO Auto-generated catch block
e3.printStackTrace();
}
PrintWriter out = null ;
try {
out = new PrintWriter (new FileWriter ("d:\\test_out.txt"));
} catch (IOException e2) {
// TODO Auto-generated catch block
e2.printStackTrace();
}
String line = null;
int lineNum = 0;
try {
while( (line = in.readLine()) != null) {
lineNum +=1;
if(lineNum == 2){
continue;
}
out.println(line);
}
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
out.flush();
out.close();
try {
in.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.