MySQL：使用 NOT IN 将联合表中的多行与主表进行比较？

Question

SELECT SQL_CALC_FOUND_ROWS e.*
FROM exercises e
LEFT JOIN exercise_targetedmuscles em ON em.exerciseID = e.exerciseID
WHERE (em.targetedMuscleID NOT IN(15,16,17,14,3,12,9,8,7,18,4,2) AND em.isPrimary = 1)
GROUP BY e.exerciseID
ORDER BY e.name ASC

我想确保锻炼的目标肌肉（可能有很多）都不在列表中“（15,16,17,14,3,12,9,8,7,18,4, 2)”，但是这只检查它找到的第一个。 如何检查来自exercise_targetedmuscles的所有匹配行，而不仅仅是第一行？

谢谢！

Answer 1

尝试这个：

SELECT SQL_CALC_FOUND_ROWS e.*
FROM exercises e
WHERE NOT EXISTS
(
    SELECT 1
      FROM  exercise_targetedmuscles em
        WHERE  em.exerciseID = e.exerciseID
                AND   em.targetedMuscleID IN(15,16,17,14,3,12,9,8,7,18,4,2)
        AND em.isPrimary = 1
)
GROUP BY e.exerciseID
ORDER BY e.name ASC