[英]MySQL statement that combines a sub-query and a JOIN is not working
SELECT i.id AS id, i.modify_date as modify_date, s.subscription as subscriptionid, p.paid/i.total AS paidratio
FROM invoices i,
(SELECT p.invoice, sum(amount) AS paid FROM payments p GROUP BY p.invoice) p
LEFT JOIN sub_to_inv s
ON i.id=s.invoice
WHERE p.invoice=i.id
AND i.corporation='3'
AND i.payer=1
我得到的错误是“ i.id上的未知列”,这是伪造的-发票(i)肯定有一个ID行。 他们都做。
sub = query的目的是找出已支付了多少发票。 例如,对于“总计”列为1000.00的发票,可以进行2或3次分期付款。 我最终在这里要做的是首先列出所有未付发票或部分发票。 但是,在进入ORDER BY阶段之前,我需要弄清楚这个错误。
对所有联接使用JOIN
语法。 不要将JOIN
语法与逗号样式的SQL-89语法混合使用。
SELECT ...
FROM invoices i
INNER JOIN (SELECT...) p
ON p.invoice=i.id
LEFT OUTER JOIN sub_to_inv s
ON i.id=s.invoice
WHERE
AND i.corporation='3'
AND i.payer=1
说明: JOIN
优先级高于逗号联接。 因此,在查询评估与i
p JOIN s
之前,先评估p JOIN s
。 因此,在子句ON i.id=s.invoice
, i
表尚不清楚,并且是无效的引用。
请参阅http://dev.mysql.com/doc/refman/5.1/en/join.html中的“ MySQL 5.0.12中的联接处理更改”之后的文档。
你可以试试这个吗?
SELECT i.id AS id, i.modify_date as modify_date, s.subscription as subscriptionid, p.paid/i.total AS paidratio
FROM invoices i
LEFT JOIN
(SELECT p.invoice, sum(amount) AS paid FROM payments p GROUP BY p.invoice) p
ON p.invoice=i.id
LEFT JOIN sub_to_inv s
ON i.id=s.invoice
WHERE i.corporation='3'
AND i.payer=1
我认为您可能会遇到问题,因为您的表在SQL中的连接顺序。 您是否尝试过使用内部联接。 也许尝试:
SELECT
i.id AS id,
i.modify_date as modify_date,
s.subscription as subscriptionid,
p.paid/i.total AS paidratio
FROM
invoices i
INNER JOIN
(SELECT
p.invoice,
sum(amount) AS paid
FROM
payments p
GROUP BY
p.invoice) p
ON
p.invoice=i.id
LEFT JOIN
sub_to_inv s
ON
i.id=s.invoice
WHERE
i.corporation='3' AND i.payer=1
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